Answer:
Step-by-step explanation:
Properties of a circumcenter;
1). Circumcenter of a triangle is a point which is equidistant from all vertices.
2). Point where perpendicular bisectors of the sides of a triangle meet is called circumcenter of the triangle.
From the picture attached,
9). AG = GB = GC = 21
10). BC = 2(DC)
= 2×16
= 32
11). By applying Pythagoras Theorem in ΔGFB,
GB² = GF² + FB²
(21)² = GF² + (19)²
441 = GF² + 361
GF² = 441 - 361
GF = 
GF = 8.9
12). By applying Pythagoras theorem in ΔGDB,
GB² = DG² + BD²
(21)² = (DG)² + (16)² [BD = DC = 16]
DG² = 441 - 256
DG = √185
DG = 13.6
Answer:
The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are.
Step-by-step explanation:
-8, -19, -30, -49 , -60
<u>Step-by-step explanation:</u>
Here we have the following sequence :
-8, -19, -30, _ , _
- First term of sequence is -8 .
- Second term of sequence is -19 :
- Third term of sequence is -30 :
- Fourth term of sequence is :
- Fifth term of sequence is :
Following sequence was an AP( Arithmetic Progression ) with first term as -8 i.e. 
and common difference 
having general equation as : 
.
A + C
(-5, -7) is 7 units to the left of point H
(-7, 7) is more than 7 units up and left of point H
the x axis is at (infinity, 0), being only 7 points up from point H
Answer:
The ratio of sixth-grade students to fifth-grade students on the team was <u>7 : 8</u>.
Step-by-step explanation:
Given:
The girl's basketball team had 8 fifth-grade students and 7 sixth-grade students.
Now, to find the ratio of sixth-grade students to fifth-grade students on the team.
<em>Number of fifth-grade students = 8.</em>
<em>Number of sixth-grade students = 7.</em>
Now, to get the ratio of sixth-grade students to fifth-grade students on the team :
Therefore, the ratio of sixth-grade students to fifth-grade students on the team was 7 : 8.
