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Eddi Din [679]
3 years ago
5

3 2/3+ 8 7/12 I need the work

Mathematics
2 answers:
svetlana [45]3 years ago
5 0

Answer:

12 1/4

Step-by-step explanation:

3 2/3 + 8 7/12

Convert to like denominators,

3 8/12 +8 7/12

3 + 8 = 11

8/12 + 7/12 = 15/12 or 1 3/12 simplified to 1 1/4

1 1/4 + 11 = 12 1/4

castortr0y [4]3 years ago
4 0

Answer:

\frac{49}{4}

Step-by-step explanation:

Convert each to a improper fraction

3 \frac{2}{3} = \frac{11}{3}

8\frac{7}{12} = \frac{103}{12}

\frac{11}{3} +\frac{103}{12} = \frac{49}{4}

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1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \  x\\5^2+10^2 \ \textgreater \  x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \  15\\ x^2 \ \textless \  125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \  15\\ x \ \textless \  \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \  10\\ 5^2+x^2 \ \textgreater \  10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \  5\\ x^2 \ \textgreater \  75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \  5\\ x \ \textgreater \  \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}

3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \  10\\ x^2+5^2 \ \textgreater \  10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}
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Step-by-step explanation:

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