1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5
sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
cos Ф>0 ⇔ sec Ф>0 ⇔ sec Ф=+ 13/5
cos Ф=1/secФ
cos Ф=1 / 13/5=5/13
we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1 ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0 ⇒ sin Ф>0 ⇒sin Ф=12/13
answer: d.12/13
other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13
answer: d.12/13
Answer:
sinФ = 8/17
cosФ = 15/17
tan Ф = 8/15
csc Ф = 17/8
sec Ф = 17/15
cot Ф = 15/8
Step-by-step explanation:
Let us revise the trigonometry functions
- Sin(x) = opposite/hypotenuse
- Cos(x) = adjacent/hypoteouse
- Tan(x) = opposite/adjacent
- Csc(x) = hypotenuse/opposit
- Sec(x) = hypotenues/adjacent
- Cot(x) = adjacent/opposite
In the given figure
The opposite side to angle Ф = 8
The adjacent side to angle Ф = 15
Find the hypotenuse using Pythagoras' theorem




Let us use the rules above to find the trigonometry functions
sinФ = 8/17
cosФ = 15/17
tan Ф = 8/15
csc Ф = 17/8
sec Ф = 17/15
cot Ф = 15/8
Answer: $18.15
Step-by-step explanation:
$ 4.50 + $13.65 = total amount due
X=-4y+2
3(-4y+2)+2y=11
-12y+6+2y=11
-10y+6=11
-6=-6
-10y=5
y=-1/2
3x+2(-1/2)=11
3x-1=11
+1=+1
3x=12
x=4
Solution:(-1/2,4)
The smaller triangle is 1/6 the size of the large one ( 5/30 = 1/
Area is squared 1/6 ^2 = 1/36
Multiply the area of the large triangle by 1/36:
270 x 1/36 = 270 /36 = 7.5
The area is 7.5 cm^2
The answer is A.