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IrinaVladis [17]
3 years ago
8

SHORT ANSWER

Mathematics
1 answer:
Degger [83]3 years ago
7 0
(-5,1)(6,-2)
slope = (-2-1) / (6-(-5) = -3/(6 + 5) = -3/11

y = mx + b
slope(m) = -3/11
(-5,1)...x = -5 and y = 1
now we sub and find b, the y int
1 = -3/11(-5) + b
1 = 15/11 + b
1 - 15/11 = b
11/11 - 15/11 = b
-4/11 = b
equation in slope int form : y = -3/11x - 4/11
3/11x + y = - 4/11....multiply by 11
3x + 11y = -4 <== standard form

(4,-2)(4,8).....if u will notice, both the x values are the same. This means the lines are vertical with an undefined slope. Your equation is : x = 4. 
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If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (u/v)(x)
choli [55]

Answer:

c) -x^3 + x^2 - 1

Step-by-step explanation:

Given: u (x) = x^5 - x^4 +x^2 and v(x) = -x^2

(u/v)(x) = u(x)/v(x)

Now plug in the given functions in the above formula, we get

= (x^5 - x^4 + x^2) / -x^2

We can factorize the numerator.

In x^5 - x^4 + x^2. the common factor is x^2, so we can take it out and write the remaining terms in the parenthesis.

= x^2 (x^3 - x^2 + 1) / - x^2

Now we gave x^2 both in the numerator and in the denominator, we can cancel it out.

(u/v)(x) = (x^3 - x^2 + 1) / -1

When we dividing the numerator by -1, we get

(u/v)(x) = -x^3 + x^2 - 1

Answer: c) -x^3 + x^2 - 1

Hope you will understand the concept.

Thank you.

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