Answer:
x= 7.87298334621 x=.12701665379
Step-by-step explanation:
This is in standard form so we have to factor this into
x^2-8x + 16 + 1 = 16
(x-4)^2 = 15
(x-4) =
x-4= ± 3.87298334621
x-4 = 3.87298334621 x-4= -3.87298334621
x= 7.87298334621 x=.12701665379
Using the binomial distribution, it is found that the mean and the standard deviation of variable x are given as follows:
It is the probability of exactly <u>x successes on n repeated trials, with p probability</u> of a success on each trial.
The expected value of the binomial distribution is:
E(X) = np
The standard deviation of the binomial distribution is:
In this problem, we have that the parameters are given as follows:
n = 4, p = 0.75.
Hence the mean and the standard deviation are given as follows:
More can be learned about the binomial distribution at brainly.com/question/24863377
#SPJ1
Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e. and
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and .
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
