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3 years ago

How do you solve 5+4(x+9)=-3

2 answers:

6 0

Final answer: x=-11
1. distribute 4(x+9)
5+4x+36=-3
2. combine like terms
4x + 41 = -3
3. subtract 41 from each side
4x = -44
4. divide 4 from each side
x=-11

sladkih [1.3K]3 years ago

4 0

Answer:

Step-by-step explanation:

First you would distribute the 4 with both of the values inside the parenthesis. So 4 times 1x (cause theirs always an invisible 1 beside the x or a -1 if it is a -x) would be 4x and 4 times 9 would be 36. Now you have the problem, 5+4x+36= -3 then you would have to get x alone on one side. So you would subtract 36 from both 36 and -3. That would get you to 5+4x= -39 then you would do the same thing but with the 5. So 4x = -44 ( you can only subtract the number if they have the same values like 4x - 3x, but, that does not apply for multiplying and or dividing). Then you would divide 4x by -44 and get -11 and that would cancel out the 4 so X= -11.

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Graph y > -1/3x+5<br><img src="https://tex.z-dn.net/?f=y%20%3E%20%20-%20%20%5Cfrac%7B1%7D%7B%203%20%7D%20x%20%2B%205" id="Tex

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Explanation:

The function is $y>-\frac{1}{3} x+5$

To graph the function, let us find the x and y intercepts.

To find x-intercept, let us substitute y=0 in the function $y>-\frac{1}{3} x+5$

$\begin{aligned}0 &=-\frac{1}{3} x+5 \\-5 &=-\frac{1}{3} x \\x &=15\end{aligned}$

Thus, the x-intercept is $(15,0)$

To find the y-intercept, let us substitute x=0, we get,

$\begin{aligned}&y=-\frac{1}{3}(0)+5\\&y=5\end{aligned}$

Thus, the y-intercept is $(0,5)$

The graph has no asymptotes.

To plot the points in the graph, we need to substitute the values for x in the function $y>-\frac{1}{3} x+5$ , to find the y-values.

The points are $(-2,5.667),(-1,5.333),(1,4.667),(2,4.333),(3,4)$ . The image of the graph and table is attached below:

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