How do I solve questions like this?!

I have a question and I cant seem figure it out. It says( Triangle ABC is a right triangle. Angle B is the right angle, side A i

pychu [463]

Answer:

you need to draw a triangle of given dimensions

Step-by-step explanation:

if B is right angle triangle then you can assume that either AB or BC is base and other one is perpendicular. So that makes AC hypotenuse

so let's assume BC is base of 6 cm. so draw a base of 6 cm line , name it BC

then draw a 90 degree angle on B keeping BC as Base . now length of perpendicular would be 4.5 cm. this perpendicular would be AB

no join A and C . length of AC should be 7.5 cm. if it's not then something is wrong in given question.

8 0

3 years ago

What is 127 to the nearest 10

finlep [7]

Answer:The answer is 130

Step-by-step explanation:

3 0

3 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

4 years ago

Reduce to the lowest terms<br> 1. 4x^3 y^4 / -8xy^2 <br> 2. 3m^2-3n^2 / 6m+6n

lawyer [7]

1.
$\dfrac{4x^{3}y^{4}}{-8xy^{2}}=\dfrac{4}{-8}\cdot x^{3-1}y^{4-2}=\dfrac{-x^{2}y^{2}}{2}$

2.
$\dfrac{3m^{2}-3n^{2}}{6m+6n}=\dfrac{3}{6}\cdot \dfrac{(m+n)(m-n)}{m+n}=\dfrac{m-n}{2}$

3 0

4 years ago

What is 36/10 as a decimal

yawa3891 [41]

.3600000000000000000000000000000000000000000000000000

6 0

3 years ago

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