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stepladder [879]
3 years ago
11

Algebra 1:Help me factor this expression

Mathematics
1 answer:
Montano1993 [528]3 years ago
6 0
9x^2y^2=200
x^2y^2=200/3
Take square both side
xy=10√2/3
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Which is a possible measure of DCA in the triangle below?
krok68 [10]

Answer:

70°

Step-by-step explanation:

The total angle in a triangle is 180°. The total angle in a straight line is 180°. From the image attached, the ∠DCA must be greater than 45° because ∠BCA is greater than 90°. This means that ∠DCA is not 36° or 38° or 40° but it is 70°.

Therefore ∠DCA = 70°.

∠BCA + ∠DCA = 180° (angle on a straight line)

∠BCA = 180 - ∠DCA = 180 - 70 = 110°

∠BCA  + ∠BAC + 40 = 180° (angle in a triangle)

∠BAC = 180 - 110 - 40 = 30°

5 0
3 years ago
Seven more than double a number one is equal to five less than triple that number. What is that number?
Inga [223]

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-\frac{2}{5}

Step-by-step explanation:

7+2n=5-3n

2n+3n=5-7\\5n=-2\\n=-\frac{2}{5}

6 0
3 years ago
How many solutions does this have
RSB [31]

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one solution

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Suponha que uma variável assume os valores: 11 – 8 – 7 – a – 16 – 10 Determine a de modo que a média aritmética seja igual 11.
Elenna [48]

Answer:

a = 14  

Step-by-step explanation:

The mean is the sum of the values divided by the number of values.

\begin{array}{rcl}\text{Mean}&= &\dfrac{11 + 8 + 7 + a + 16 + 10}{6}\\\\\dfrac{52 + a}{6}& = & 11\\52 + a & = & 66\\a & = & 66 - 52\\& = & \mathbf{14}\\\end{array}

4 0
4 years ago
Find the distance between xequals[Start 2 By 1 Matrix 1st Row 1st Column 8 2nd Row 1st Column negative 5 EndMatrix ]and yequals[
kherson [118]

Answer:

Distance =√(x₁ - y₁)²+ (x₂ - y₂)² = √97 = 9.85

Step-by-step explanation:

The Matrix X and Y could also be referred to as vectors in Rⁿ dimensions.

if Vector X = ( x₁ , x₂)   and  Vector  Y = (y₁ , y₂)

then, Distance (X-Y) = ||X-Y|| = √(x₁ - y₁)²+ (x₂ - y₂)²

where, x₁ = 8, x₂ = -5   and  y₁ = -1 , y₂ = -9

Distance = √(8 - (-1))²+ (-5 - (-9))² = √9² + 4² =√97 = 9.85

4 0
3 years ago
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