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3 years ago

Match the following three dimensional figures to the appropiate nets below.

Mathematics

1 answer:

Anna35 [415]3 years ago

7 0

In my opinion it’s F

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3 years ago

Identify the slope and y-intercept of the<br> line!

marta [7]

Slope of the line = $\frac{1}{2}$ .

y-intercept of the line = -7.

Solution:

General form of equation of a line:

y = mx + c

where m is the slope and c is the y-intercept of the line.

Equation of a line:

$$y=\frac{1}{2} x-7$

To compare this with general equation.

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5 0

3 years ago

Please help i beg i never get these right

Anuta_ua [19.1K]

Answer:

$\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}$

Step-by-step explanation:

Given

$\sin(105^o)$

Required

Solve

Using sine rule, we have:

$\sin(A + B) = \sin(A)\cos(B) + \sin(B)\cos(A)$

This gives:

$\sin(105^o) = \sin(60 + 45)$

So, we have:

$\sin(60 + 45) = \sin(60)\cos(45) + \sin(45)\cos(60)$

In radical forms, we have:

$\sin(60 + 45) = \frac{\sqrt 3}{2} * \frac{\sqrt 2}{2} + \frac{\sqrt 2}{2} * \frac{1}{2}$

$\sin(60 + 45) = \frac{\sqrt 6}{4} + \frac{\sqrt 2}{4}$

Take LCM

$\sin(60 + 45) = \frac{\sqrt 6 + \sqrt 2}{4}$

Rewrite as:

$\sin(60 + 45) = \frac{\sqrt 2 + \sqrt 6}{4}$

Hence:

$\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}$

3 0

3 years ago