Answer:
B
Step-by-step explanation:
Rearrange the equation making x the subject
y = x - ( multiply through by 2 to clear the fractions )
2y = x - 3 ( add 3 to both sides )
2y + 3 = x
Change y back into terms of x with x being the inverse function, that is
y = 2x + 3 → B
Answer:
m∠6 = 42° m∠7 = 138
Step-by-step explanation:
Since we have the measure of angle 4, using the rule of verticle opposites, this means that the opposites are the same. so 4 = 2, and 6 = 8, and 1 = 3, and 5 = 7.
And since there is also the rule of same side correspondence, this means 4 = 8, and 6 = 2.
This means that since 4 = 42°, and 4 = 2, and 2 = 6, then m∠6 = 42°
and since 7 is opposite of 6 on a straight line, you can subtract 42 from 180 degrees to get the degree of 7.
180 - 42 = 138
so m∠7 = 138°
If it was line symmetry it would need to repeat the same shape twice, which the first follows but the second doesn’t.
if it was rotational, you would need to be able to take the shape in the top right and rotate it counterclockwise or clockwise to get the shape that locks in place. that doesn’t follow that.
both line and rotational symmetry is incorrect because the first example would need to lock up inside the right side of that example.
the answer is C
Since (f/g)(x) = f(x)/g(x) for x to be in the domain of (f/g)(x) it must be in the domain of f and in the domain of g. You also need to insure that g(x) is not zero since f(x) is divided by g(x). Thus there are 3 conditions. x must be in the domain of f: f(x) = 3x -5 and all real numbers x are in the domain of x.
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find ( f o f )(x).
( f o f )(x) = f ( f (x))
= f (2x + 3)
= 2( ) + 3 ... setting up to insert the input
= 2(2x + 3) + 3
= 4x + 6 + 3
= 4x + 9
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o g)(x).
(g o g)(x) = g(g(x))
= –( )2 + 5 ... setting up to insert the input
= –(–x2 + 5)2 + 5
= –(x4 – 10x2 + 25) + 5
= –x4 + 10x2 – 25 + 5
= –x4 + 10x2 – 20
Answer:
When you multiply two numbers or variables with the same base, you simply add the exponents. When you multiply expressions with the same exponent but different bases, you multiply the bases and use the same exponent.
Step-by-step explanation: