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lilavasa [31]
3 years ago
11

What is the side length of a cube with the volume 343cm3?

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
7 0
The side length is 7 because 7*7*7 is 343 cm3
prohojiy [21]3 years ago
4 0
Volume is length times width times height so 343 divided by 7 so seven is the answer
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You spin the spinner below once. What is the P(getting a number less than 5)?
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Answer:

3/4

Step-by-step explanation:

Other than 5 there are 3 other numbers that could be chosen so its 3/4 chances

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Step-by-step explanation:

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Factor completely: (4c - x)^2 - (2c + 3x)^2
azamat

Answer:

Graph for (4*​2.99792e+08-​x)^​2-​(2*​2.99792e+08+​3*​x)^​2

More info

How to solve your problem

(4−)2−1(2+3)2

(4c−x)2−1(2c+3x)2(4c-x)^{2}-1(2c+3x)^{2}(4c−x)2−1(2c+3x)2

Simplify

1

Expand the square

(4−)2−1(2+3)2

(4c−x)2−1(2c+3x)2\left(4c-x\right)^{2}-1(2c+3x)^{2}(4c−x)2−1(2c+3x)2

(4−)(4−)−1(2+3)2

(4c−x)(4c−x)−1(2c+3x)2(4c-x)(4c-x)-1(2c+3x)^{2}(4c−x)(4c−x)−1(2c+3x)2

2

Distribute

(4−)(4−)−1(2+3)2

(4c−x)(4c−x)−1(2c+3x)2{\color{#c92786}{(4c-x)(4c-x)}}-1(2c+3x)^{2}(4c−x)(4c−x)−1(2c+3x)2

4(4−)−(4−)−1(2+3)2

4c(4c−x)−x(4c−x)−1(2c+3x)2{\color{#c92786}{4c(4c-x)-x(4c-x)}}-1(2c+3x)^{2}4c(4c−x)−x(4c−x)−1(2c+3x)2

3

Distribute

4(4−)−(4−)−1(2+3)2

4c(4c−x)−x(4c−x)−1(2c+3x)2{\color{#c92786}{4c(4c-x)}}-x(4c-x)-1(2c+3x)^{2}4c(4c−x)−x(4c−x)−1(2c+3x)2

162−4−(4−)−1(2+3)2

16c2−4cx−x(4c−x)−1(2c+3x)2{\color{#c92786}{16c^{2}-4cx}}-x(4c-x)-1(2c+3x)^{2}16c2−4cx−x(4c−x)−1(2c+3x)2

4

Distribute

162−4−(4−)−1(2+3)2

16c2−4cx−x(4c−x)−1(2c+3x)216c^{2}-4cx{\color{#c92786}{-x(4c-x)}}-1(2c+3x)^{2}16c2−4cx−x(4c−x)−1(2c+3x)2

162−4−4+2−1(2+3)2

16c2−4cx−4cx+x2−1(2c+3x)216c^{2}-4cx{\color{#c92786}{-4cx+x^{2}}}-1(2c+3x)^{2}16c2−4cx−4cx+x2−1(2c+3x)2

5

Combine like terms

162−4−4+2−1(2+3)2

16c2−4cx−4cx+x2−1(2c+3x)216c^{2}{\color{#c92786}{-4cx}}{\color{#c92786}{-4cx}}+x^{2}-1(2c+3x)^{2}16c2−4cx−4cx+x2−1(2c+3x)2

162−8+2−1(2+3)2

16c2−8cx+x2−1(2c+3x)216c^{2}{\color{#c92786}{-8cx}}+x^{2}-1(2c+3x)^{2}16c2−8cx+x2−1(2c+3x)2

6

Expand the square

162−8+2−1(2+3)2

16c2−8cx+x2−1(2c+3x)216c^{2}-8cx+x^{2}-1\left(2c+3x\right)^{2}16c2−8cx+x2−1(2c+3x)2

162−8+2−1(2+3)(2+3)

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7

Distribute

162−8+2−1(2+3)(2+3)

16c2−8cx+x2−1(2c+3x)(2c+3x)16c^{2}-8cx+x^{2}-1{\color{#c92786}{(2c+3x)(2c+3x)}}16c2−8cx+x2−1(2c+3x)(2c+3x)

162−8+2−1(2(2+3)+3(2+3))

16c2−8cx+x2−1(2c(2c+3x)+3x(2c+3x))16c^{2}-8cx+x^{2}-1({\color{#c92786}{2c(2c+3x)+3x(2c+3x)}})16c2−8cx+x2−1(2c(2c+3x)+3x(2c+3x))

8

Distribute

162−8+2−1(2(2+3)+3(2+3))

16c2−8cx+x2−1(2c(2c+3x)+3x(2c+3x))16c^{2}-8cx+x^{2}-1({\color{#c92786}{2c(2c+3x)}}+3x(2c+3x))16c2−8cx+x2−1(2c(2c+3x)+3x(2c+3x))

162−8+2−1(42+6+3(2+3))

16c2−8cx+x2−1(4c2+6cx+3x(2c+3x))16c^{2}-8cx+x^{2}-1({\color{#c92786}{4c^{2}+6cx}}+3x(2c+3x))16c2−8cx+x2−1(4c2+6cx+3x(2c+3x))

9

Distribute

162−8+2−1(42+6+3(2+3))

16c2−8cx+x2−1(4c2+6cx+3x(2c+3x))16c^{2}-8cx+x^{2}-1(4c^{2}+6cx+{\color{#c92786}{3x(2c+3x)}})16c2−8cx+x2−1(4c2+6cx+3x(2c+3x))

162−8+2−1(42+6+6+92)

16c2−8cx+x2−1(4c2+6cx+6cx+9x2)16c^{2}-8cx+x^{2}-1(4c^{2}+6cx+{\color{#c92786}{6cx+9x^{2}}})16c2−8cx+x2−1(4c2+6cx+6cx+9x2)

10

Combine like terms

162−8+2−1(42+6+6+92)

16c2−8cx+x2−1(4c2+6cx+6cx+9x2)16c^{2}-8cx+x^{2}-1(4c^{2}+{\color{#c92786}{6cx}}+{\color{#c92786}{6cx}}+9x^{2})16c2−8cx+x2−1(4c2+6cx+6cx+9x2)

162−8+2−1(42+12+92)

16c2−8cx+x2−1(4c2+12cx+9x2)16c^{2}-8cx+x^{2}-1(4c^{2}+{\color{#c92786}{12cx}}+9x^{2})16c2−8cx+x2−1(4c2+12cx+9x2)

11

Distribute

162−8+2−1(42+12+92)

16c2−8cx+x2−1(4c2+12cx+9x2)16c^{2}-8cx+x^{2}{\color{#c92786}{-1(4c^{2}+12cx+9x^{2})}}16c2−8cx+x2−1(4c2+12cx+9x2)

162−8+2−42−12−92

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12

Combine like terms

162−8+2−42−12−92

16c2−8cx+x2−4c2−12cx−9x2{\color{#c92786}{16c^{2}}}-8cx+x^{2}{\color{#c92786}{-4c^{2}}}-12cx-9x^{2}16c2−8cx+x2−4c2−12cx−9x2

122−8+2−12−92

12c2−8cx+x2−12cx−9x2{\color{#c92786}{12c^{2}}}-8cx+x^{2}-12cx-9x^{2}12c2−8cx+x2−12cx−9x2

13

Combine like terms

122−8+2−12−92

12c2−8cx+x2−12cx−9x212c^{2}{\color{#c92786}{-8cx}}+x^{2}{\color{#c92786}{-12cx}}-9x^{2}12c2−8cx+x2−12cx−9x2

122−20+2−92

12c2−20cx+x2−9x212c^{2}{\color{#c92786}{-20cx}}+x^{2}-9x^{2}12c2−20cx+x2−9x2

14

Combine like terms

122−20+2−92

12c2−20cx+x2−9x212c^{2}-20cx+{\color{#c92786}{x^{2}}}{\color{#c92786}{-9x^{2}}}12c2−20cx+x2−9x2

122−20−82

Step-by-step explanation:

7 0
3 years ago
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A box is formed by cutting squares from the corners of a rectangular piece of cardboard. The volume of the box is found by the e
sineoko [7]

Answer:

A. (0, 5)

Step-by-step explanation:

Physically speaking, the volume of the box and the side of the square cutout are positive value. So that the following inequations must be satisfied:

h > 0 (1)

16-2\cdot h >0 (2)

10-2\cdot h > 0 (3)

From (1), (2), (3) we find that:

(1):

h > 0

(2):

16 > 2\cdot h

8 > h

h < 8

(3):

10 > 2\cdot h

5 > h

h < 5

We see that equation above is the multiplication of a first grade monomial and two first grade binomials, which means that:

h > 0 \,\land\,h < 5\,\land\,h< 8

0< h < 5

In other words, the reasonable domain for this situation is A.

5 0
3 years ago
HELP FOR THE 2ND TIME I WASTED MY POINTS 1ST TIME I WASNT AT SCHOOL!
lana66690 [7]

Answer:The last option

Step-by-step explanation:the absolute value bars make it positive but the negative on the outside of those bars make it negative, this -|3|=-3 and -|2|=-2. Furthermore, the double negative on the last two dots make a positive, thus -(-2)=2 and -(-3)=3. With this in mind it is -3,-2,2,3 and -|3|,-|2|,-(-2),-(-3)

5 0
3 years ago
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