I find the following method easiest to factor this equation.
1. First, fill in what you know would be the factors for the first value, 3x^2. The number 3 only has 2 factors: 3 and 1. Therefore, we know the first values are:
(3x _____)(x_____)
2. Next, figure out what the possible factors for the last value would be (-6). The following combinations are possible:
2 and -3 OR -3 and 2
-2 and 3 OR 3 and -2
-1 and 6 OR 6 and -1
1 and -6 OR -6 and 1
3. Plug in the combinations into step 1 and see which gives you the correct answer:
<span>(3x + 2)(x - 3) = 3x^2 - 7x - 6 --> no
</span>(3x - 3)(x + 2<span>) = 3x^2 + 3x - 6 --> no
</span>(3x - 2)(x + 3) = 3x^2 + <span>7x - 6 --> YES</span>
Answer:
Step-by-step explanation:
Now we know that
sec²θ -tan² θ= 1 ,
So tan²θ =sec²θ - 1
So the left of the given equation will be
sec²20 + sec²40 +sec²80 - 3
So
1/cos²20+1/cos²49+1/cos²80 -3
Remember sec θ= 1/cosθ
So
= since secθ = 1/cosθ
we have
= 1.1324 + 1.7040 + 33.1634 - 3
= 35.9998 - 3
= 33
Answer:
So do you want the roots? If so it is
x ≈ −
1.37049747
, 1.13336413
but rounded is x = -1 ; x = 1
Step-by-step explanation:
Answer:
b²
Step-by-step explanation:
To complete the square
add ( half the coefficient of the x- term)² to x² + bx
x² + 2( b )x + ( b )²
= x² + bx + b²
Answer:
Logic with the use of Truth Table
Step-by-step explanation: a) Oleg is a math major= P; Oleg is a economic major=Q; Oleg is required to take math 362=R; Oleg is not required to take 362=←R
b)i) Oleg is a math major or Oleg is an economic major:
P║ Q ║ P∨Q
T T T
T F T
F T T
F F F
ii) Oleg is a math major, then Oleg is required to take Math 362:
P║ R ║ P∧ R
T T T
T F F
F T F
F F F
iii) Oleg is an economic major or Oleg is not required to take Math 362:
Q║ ←R ║ Q ∨ ←R
T T T
T F T
F T T
F F F
c) It is valid because Oleg can only take Math 362 since Oleg is a math major, therefore, it follows that, R ∧ ( P ∨ Q) is valid.