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REY [17]
3 years ago
8

Police use the formula:

Mathematics
1 answer:
sashaice [31]3 years ago
4 0

Answer:

62.3 miles per hours.

Step-by-step explanation:

The given formula is

v=\sqrt{20L}

Police use this formula to estimate the speed of a car, v , in miles per hour, based on the length, L , in feet, of its skid marks when suddenly braking on a dry, asphalt road.

It is given that car's skid marks is 194 feet at the scene of an accident.

We need to find the speed of car at the time of accident.

Substitute L=194 in the above formula.

v=\sqrt{20(194)}

v=\sqrt{3880}

v=62.289646

v\approx 62.3

Therefore, the speed of car is 62.3 miles per hours.

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Use aleks calculator to write 25/24 as a decimal rounded to the nearest hundredth ​
Alex_Xolod [135]

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3 years ago
A flagpole stands atop a building. From a point 10' away from the base of a building, the angles of elevation of the top and bot
Debora [2.8K]

Answer:

  building: 51.4 ft

  flagpole: 5.3 ft

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

If we let b and p represent the heights of the building and flagpole, respectively, then we can write two equations using the tangent relation:

  tan(79°) = b/10

  tan(80°) = (b +p)/10

Multiplying these equations by 10 gives the values we're interested in.

  b = 10·tan(79°) ≈ 51.4 . . . feet

  b +p = 10·tan(80°) ≈ 56.7 . . . feet

Then the height of the flagpole is ...

  p = (b+p) -b = (56.7 ft) -(51.4 ft) = 5.3 ft

The building is 51.4 ft tall.

The flagpole is 5.3 ft tall.

4 0
3 years ago
A fair spinner is spun. <br> Work out the probability of getting a factor of 9.
Deffense [45]
Whats it out of is it 1-10 or somthing else
7 0
3 years ago
Read 2 more answers
Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the diagonal distance across a r
Zepler [3.9K]
<h2>∴Will ran 13.55 yards more than James.</h2>

Step-by-step explanation:

Given Will ran the diagonal distance across a square field measuring 40 yards each sides .

∴The distance covered by Will was =\sqrt{40^{2}+40^2 } yards

                                                         = 40\sqrt{2} yards=56.56 yards

Again James ran diagonal distance across a rectangle field with a length of 25 yards and a width of 35 yards.

So,distance covered by James was =\sqrt{25^2+35^2} yards

                                                             =5\sqrt{74} yards = 43.01 yards

∴Will ran longer distance.

∴Will ran 13.55 yards more than James.

4 0
4 years ago
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