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3 years ago

ANSWER THIS PLEASE!

Mathematics

1 answer:

Minchanka [31]3 years ago

4 0

Answer:

can't see question

Step-by-step explanation:

IDK

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Cho is making a rectangular garden, where the length is x feet and

Studentka2010 [4]

Answer:16x-6

Step-by-step explanation:4(4x-1) distributed is 16x-6

7 0

3 years ago

6) Supplementary Exercise 5.51

tresset_1 [31]

Answer:

$P(X \le 4) = 0.7373$

$P(x \le 15) = 0.0173$

$P(x > 20) = 0.4207$

$P(20\ge x \le 24)= 0.6129$

$P(x = 24) = 0.0236$

$P(x = 15) = 1.18\%$

Step-by-step explanation:

Given

$p = 80\% = 0.8$

The question illustrates binomial distribution and will be solved using:

$P(X = x) = ^nC_xp^x(1 - p)^{n-x}$

Solving (a):

Given

$n =5$

Required

$P(X\ge 4)$

This is calculated using

$P(X \le 4) = P(x = 4) +P(x=5)$

This gives:

$P(X \le 4) = ^5C_4 * (0.8)^4*(1 - 0.8)^{5-4} + ^5C_5*0.8^5*(1 - 0.8)^{5-5}$

$P(X \le 4) = 5 * (0.8)^4*(0.2)^1 + 1*0.8^5*(0.2)^0$

$P(X \le 4) = 0.4096 + 0.32768$

$P(X \le 4) = 0.73728$

$P(X \le 4) = 0.7373$ --- approximated

Solving (b):

Given

$n =25$

Required

$P(X\le 15)$

This is calculated as:

$P(X\le 15) = 1 - P(x>15)$ --- Complement rule

$P(x>15) = P(x=16) + P(x=17) + P(x =18) + P(x = 19) + P(x = 20) + P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)$

$P(x > 15) = {25}^C_{16} * p^{16}*(1-p)^{25-16} +{25}^C_{17} * p^{17}*(1-p)^{25-17} +{25}^C_{18} * p^{18}*(1-p)^{25-18} +{25}^C_{19} * p^{19}*(1-p)^{25-19} +{25}^C_{20} * p^{20}*(1-p)^{25-20} +{25}^C_{21} * p^{21}*(1-p)^{25-21} +{25}^C_{22} * p^{22}*(1-p)^{25-22} +{25}^C_{23} * p^{23}*(1-p)^{25-23} +{25}^C_{24} * p^{24}*(1-p)^{25-24} +{25}^C_{25} * p^{25}*(1-p)^{25-25}$

$P(x > 15) = 2042975 * 0.8^{16}*0.2^9 +1081575* 0.8^{17}*0.2^8 +480700 * 0.8^{18}*0.2^7 +177100 * 0.8^{19}*0.2^6 +53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0$

$P(x > 15) = 0.98266813045$

So:

$P(X\le 15) = 1 - P(x>15)$

$P(x \le 15) = 1 - 0.98266813045$

$P(x \le 15) = 0.01733186955$

$P(x \le 15) = 0.0173$

ii)

$P(x>20)$

This is calculated as:

$P(x>20) = P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)$

$P(x > 20) = 12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0$

$P(x > 20) = 0.42067430925$

$P(x > 20) = 0.4207$

iii)

$P(20\ge x \le 24)$

This is calculated as:

$P(20\ge x \le 24) = P(x = 20) + P(x = 21) + P(x = 22) + P(x =23) + P(x = 24)$

$P(20\ge x \le 24)= 53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1$

$P(20\ge x \le 24)= 0.61291151859$

$P(20\ge x \le 24)= 0.6129$

iv)

$P(x = 24)$

This is calculated as:

$P(x = 24) = 25* 0.8^{24}*0.2^1$

$P(x = 24) = 0.0236$

Solving (c):

$P(x = 15)$

This is calculated as:

$P(x = 15) = {25}^C_{15} * 0.8^{15} * 0.2^{10}$

$P(x = 15) = 3268760 * 0.8^{15} * 0.2^{10}$

$P(x = 15) = 0.01177694905$

$P(x = 15) = 0.0118$

Express as percentage

$P(x = 15) = 1.18\%$

The calculated probability (1.18%) is way less than the advocate's claim.

Hence, we do not believe the claim.

5 0

3 years ago

Please help, due soon. Find the length of the arc. Use exact answer

Simora [160]

Answer:

off topic- and I'm sorry for that- but hi stay- :)

8 0

3 years ago

Read 2 more answers

X + y =125<br> 5x + 8y = 775

muminat

Answer:

x=75, y = 50

Step-by-step explanation:

Solve the following system:

{x + y = 125 | (equation 1)

5 x + 8 y = 775 | (equation 2)

Swap equation 1 with equation 2:

{5 x + 8 y = 775 | (equation 1)

x + y = 125 | (equation 2)

Subtract 1/5 × (equation 1) from equation 2:

{5 x + 8 y = 775 | (equation 1)

0 x - (3 y)/5 = -30 | (equation 2)

Multiply equation 2 by -5/3:

{5 x + 8 y = 775 | (equation 1)

0 x+y = 50 | (equation 2)

Subtract 8 × (equation 2) from equation 1:

{5 x+0 y = 375 | (equation 1)

0 x+y = 50 | (equation 2)

Divide equation 1 by 5:

{x+0 y = 75 | (equation 1)

0 x+y = 50 | (equation 2)

Collect results:

Answer: {x = 75 , y = 50

8 0

3 years ago

Read 2 more answers

Marcus states that angle ORP and angle LRP are a linear pair. Which best describes his statement?

svetlana [45]

Answer:

He is incorrect. Ray RO and ray RL are not opposite rays.

Step-by-step explanation:

Two angles are linear pair if they are supplementary and share a leg.

∠ORP and ∠LRP are not supplementary, because ray RO and ray RL are not opposite rays.

Therefore, ∠ORP and ∠LRP are not linear pair.

correct me if this is wrong

6 0

3 years ago