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3 years ago

The following chart shows a store’s coat sales for two years.

Mathematics

2 answers:

STALIN [3.7K]3 years ago

7 0

Answer:

Sales of trench coats increased 8.3 percentage points faster than total coat sales.

Step-by-step explanation:

2006:

top coats is 297,

parkas is 210,

jackets is 213,

raincoats is 137,

trench coats is 103

Total: $297+210+213+137+103=960$

2007:

topcoats is 223,

parkas is 210,

jackets is 285,

raincoats is 259,

trench coats is 127

Total: $223+210+285+259+127=1,104$

Percent increase in total sales:

$\dfrac{1,104-960}{960}\cdot 100\%=15\%$

Percent increase in sales of trench coats:

$\dfrac{127-103}{103}\cdot 100\%\approx 23.3\%$

Since $23.3\%-15\%=8.3\%,$ sales of trench coats increased 8.3 percentage points faster than total coat sales.

svp [43]3 years ago

3 0

Answer:

B is da way

Step-by-step explanation:

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Temka [501]

Answer:

37.5

Step-by-step explanation:

180-75 = 105

180 is the sum of all the angle in a triangle

180-105 = 75

75/2 = x becuz the triangle is icoceles

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8 0

3 years ago

For each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to

kiruha [24]

Answer:

D) 11/3

Step-by-step explanation:

Let x represent monthly salary.

We have been given that for each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to charity.

Salary earned in 11 months would be $11x$ .

Money donated in 11 months would be $\frac{11x}{10}$ .

Further we are told that in December, the worker earned N times his usual monthly salary and donated one-fifth of his earnings to charity.

Salary for December would be $Nx$ .

Money donated in December would be $\frac{Nx}{5}$ .

The worker's charitable contributions totaled one-eighth of his earnings for the entire year that is $\frac{1}{8}\cdot (11x+Nx)$ .

$\frac{11x}{10}+\frac{Nx}{5}=\frac{1}{8}\cdot (11x+Nx)$

Dividing whole equation by x, we will get:

$\frac{11x}{10x}+\frac{Nx}{5x}=\frac{1}{8x}\cdot x(11+N)$

$\frac{11}{10}+\frac{N}{5}=\frac{1}{8}\cdot (11+N)$

$\frac{11}{10}+\frac{N}{5}=\frac{11}{8}+\frac{N}{8}$

Combine like terms:

$\frac{N}{5}-\frac{N}{8}=\frac{11}{8}-\frac{11}{10}$

$\frac{N}{5}*40-\frac{N}{8}*40=\frac{11}{8}*40-\frac{11}{10}*40$

$8N-5N=11*5-11*4$

$3N=55-44$

$3N=11$

$\frac{3N}{3}=\frac{11}{3}\\\\N=\frac{11}{3}$

Therefore, the value of N is 11/3 and option D is the correct choice.

4 0

3 years ago

For two functions, a(x) and b(x), a statement is made that a(x) = b(x) at x = 2. What is definitely true about x = 2?

klio [65]

I believe that it should be that the functions intersect at x=2

8 0

3 years ago

Read 2 more answers

How do you write 0.000003939 in scientific notation?

Jlenok [28]

3.939x10^-6
That should be right.

6 0

2 years ago

A stick of butter in the shape of a rectangular prism has a length of 8 inches, a width of 3 inches, and a height of 3 inches. W

SVEN [57.7K]

Answer:

$72in^3$

Step-by-step explanation:

the information we know about the shape of the stick of butter:

$length = 8in$

$width = 3in$

$height=3in$

The formula for the volume of a rectangular prism is:

$volume=length*width*height$

we find the volume by multiplying ll the measurements of the stick.

So we substitute the values to find the volume and we get the following:

$volume=8in*3in*3in\\volume=72in^3$

the volume of the stick of butter is $72in^3$

5 0

3 years ago