The image doesn’t show up
The new mixture exists 56.5% peanuts.
<h3>How to estimate the total number of peanuts required for the mixture?</h3>
The first batch of 9 lb of mixed nuts possesses 40% peanuts.
This means the quantity of peanuts exists:
9
40/100 = 3.6 lb
The second batch of 9 lb of mixed nuts possesses 73% peanuts.
This means the quantity of peanuts exists:
9
73/100 = 6.57 lb
The total quantity of peanuts in the mix exists
3.6 lb + 6.57 lb = 10.17 lb
There exist 9 lb + 9 lb = 18 lb of mix.
Therefore, the percent of peanuts in the mix exists:
10.17 / 18
100 = 56.5%
The new mixture exists 56.5% peanuts.
To learn more about the total quantity refer to:
brainly.com/question/18919760
#SPJ4
Answer:
d) 1
Step-by-step explanation:
The variance of standard normal distribution is simply put as 1.
If you take it a bit further, even though not asked, the mean of a standard normal distribution is 0.
Therefore, the conclusion is that, the variance of a standard normal distribution is 1, while the mean of the same standard normal distribution is 0
Answer:
-18/7 or -2 4/7
Explanation:
-3 2/7 - ( -5/7 )
-23/7 + 5/7
-18/7 Improper fraction
-2 4/7 Mixed Number
Answer:
lope-intercept form, y=mx+b, of linear equations
Step-by-step explanation: