i thing the answer is D the last chart
Answer:
24 boxes
Step-by-step explanation:
The processor knows that the standard deviation of box weight is 0.5 pound
![\sigma = 0.5](https://tex.z-dn.net/?f=%5Csigma%20%3D%200.5)
We are supposed to find How many boxes must the processor sample to be 95% confident that the estimate of the population mean is within 0.2 pound
Formula of Error=![z \times \frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=z%20%5Ctimes%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
Since we are given that The estimate of the population mean is within 0.2 pound
So, ![z \times \frac{\sigma}{\sqrt{n}}=0.2](https://tex.z-dn.net/?f=z%20%5Ctimes%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%3D0.2)
z at 95% confidence level is 1.96
![1.96 \times \frac{0.5}{\sqrt{n}}=0.2](https://tex.z-dn.net/?f=1.96%20%5Ctimes%20%5Cfrac%7B0.5%7D%7B%5Csqrt%7Bn%7D%7D%3D0.2)
![1.96 \times \frac{0.5}{0.2}=\sqrt{n}](https://tex.z-dn.net/?f=1.96%20%5Ctimes%20%5Cfrac%7B0.5%7D%7B0.2%7D%3D%5Csqrt%7Bn%7D)
![4.9=\sqrt{n}](https://tex.z-dn.net/?f=4.9%3D%5Csqrt%7Bn%7D)
![(4.9)^2=n](https://tex.z-dn.net/?f=%284.9%29%5E2%3Dn)
![24.01=n](https://tex.z-dn.net/?f=24.01%3Dn)
Hence the processor must sample 24 boxes to be 95% confident that the estimate of the population mean is within 0.2 pound
Answer:
John Hughes won in the month a total of $4405
Step-by-step explanation:
if we have that Jhon earns a salary of $ 2800 and a commission of 7.5% of the sales he made for a value of $ 21400
to know the gain of jhon we have to add the basic salary with the percentage of what he sold
x = 2800 + 21400 * 7.5%
7.5% can be expressed as 7.5/100
x = 2800 + 21400 * 7.5/100
x = 2800 + 21400 * 0.075
x = 2800 + 1605
x = 4405
Answer:
B
Step-by-step explanation:
Given 2 sides of a triangle then the third side x is
difference of 2 sides < x < sum of 2 sides , that is
17 - 10 < x < 17 + 10
7 < x < 27
In terms of AC , then
7 < AC < 27 → B