In a normal distribution, the median is the same as the mean (25.3). The first quartile is the value of

such that

You have

For the standard normal distribution, the first quartile is about

, and by symmetry the third quartile would be

. In terms of the MCAT score distribution, these values are


The interquartile range (IQR) is just the difference between the two quartiles, so the IQR is about 8.8.
The central 80% of the scores have z-scores

such that

That leaves 10% on either side of this range, which means

You have

Converting to MCAT scores,


So the interval that contains the central 80% is

(give or take).
<span>x^2-80=0
</span><span>x^2 = 80
x^2 = 16 (5)
x = 4</span>√5 and x = -4<span>√5</span>
Answer:
w = 0, 5
Step-by-step explanation:
Answer:
bus = 43
van 12
Step-by-step explanation:
This can be solved using simultaneous equations
Let v represent the number of students that a van carries
Let b represent the number of students that a bus carries
the following equations can be derived from the question
3v + 2b = 122 eqn 1
5v + 3b = 189 eqn 2
Multiply eqn 1 by 5 and eqn 2 by 3
15v + 10b = 610 eqn 3
15v + 9b = 567 eqn 4
Subtract equation 4 from 3
b = 43
Substitute for b in equation 1
3v + 2(43) = 122
solve for v
v = 12
25-9=16 so 16 is the answer