See the attached figure to better understand the problem
we know that
tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft
CB--------> <span>how far the man is from the helicopter landing pad
</span>so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft
the answer is
the man is 198.45 ft from the helicopter landing pad
The answer is 31 feet per second :)
67.890, because 67 is greater than 6
The only thing that you need to do is Divide -2 on both sides to isolate the M. so 7/-2 M=3.5