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2 years ago

HELPPPP ASAPPP PLEASSSSEE

Mathematics

2 answers:

kolezko [41]2 years ago

5 0

Let dimes = d and quarters =q

D + q = 50

D= 50-q

0.10d + 0.25Q = 7.70

Replace d with 50-q:

0.10(50-q) + 0.25q = 7.70

Simplify:

5 -0.10q + 0.25q = 7.70

5 + 0.15q = 7.70

Subtract 5 from both sides:

0.15q = 2.70

Divide both sides by 0.15:

Q = 2.70 / 0.15

Q = 18

D = 50-18 = 32

There are 32 dimes and 18 quarters

Anastaziya [24]2 years ago

5 0

K12 be doing too much

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Find the indefinite integrals, if possible, using the formulas and techniques you have studied so far in the text.(a) 11 x4 dxTh

hoa [83]

Answer:

a) This integral can be evaluated using the basic integration rules. $\int 11x^{4}dx = \frac{11}{5} x^{5}+C$

b) This integral can be evaluated using the basic integration rules. $\int 8x^{1}x^{4}dx=\frac{4}{3}x^{6}+C$

c) This integral can be evaluated using the basic integration rules. $\int 3x^{31}x^{4}dx=\frac{x^{36}}{12}+C$

Step-by-step explanation:

a) $\int 11x^{4}dx$

In order to solve this problem, we can directly make use of the power rule of integration, which looks like this:

$\int kx^{n}=k\frac{x^{n+1}}{n+1}+C$

so in this case we would get:

$\int 11x^{4}dx=11 \frac{x^{4+1}}{4+1}+C$

$\int 11x^{4}dx=11 \frac{x^{5}}{5}+C$

b) $\int 8x^{1}x^{4}dx$

In order to solve this problem we just need to use some algebra to simplify it. By using power rules, we get that:

$\int 8x^{1}x^{4}dx=\int 8x^{1+4}dx=\int 8x^{5}dx$

So we can now use the power rule of integration:

$\int 8x^{5}dx=\frac{8}{5+1}x^{5+1}+C$

$\int 8x^{5}dx=\frac{8}{6}x^{6}+C$

$\int 8x^{5}dx=\frac{4}{3}x^{6}+C$

c) The same applies to this problem:

$\int 3x^{31}x^{4}dx=\int 3x^{31+4}dx=\int 3x^{35}dx$

and now we can use the power rule of integration:

$\int 3x^{35}dx=\frac{3x^{35+1}}{35+1}+C$

$\int 3x^{35}dx=\frac{3x^{36}}{36}+C$

$\int 3x^{35}dx=\frac{x^{36}}{12}+C$

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2 years ago

9.64 rounded to the nearest tenth

Ivanshal [37]

Hello,

9.64 rounded to the nearest tenth is 9.6.

Have A Good Day.

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