Answer:

Step-by-step explanation:
Let the number of acre of corn planted =x
Let the number of acre of soybeans planted =y
Seed costs for a farmer are $40 per acre for corn and $32 per acre for soybeans.
- Seed Cost for x acre of corn = $40x
- Seed Cost for y acre of soybeans = $32y
The farmer wants to spend no more than $5,000 on seed.
Therefore the linear inequality is:

Next, we graph the inequality

The graph is attached below.
-5 * 8 = -40 losing would make your number be multiplied by the points lost each time
Answer:
Step-by-step explanation:
A) Let x represent acres of pumpkins, and y represent acres of corn. Here are the constraints:
x ≥ 2y . . . . . pumpkin acres are at least twice corn acres
x - y ≤ 10 . . . . the difference in acreage will not exceed 10
12 ≤ x ≤ 18 . . . . pumpkin acres will be between 12 and 18
0 ≤ y . . . . . the number of corn acres is non-negative
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B) If we assume the objective is to maximize profit, the profit function we want to maximize is ...
P = 360x +225y
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C) see below for a graph
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D) The profit for an acre of pumpkins is the highest, so the farmer should maximize that acreage. The constraint on the number of acres of pumpkins comes from the requirement that it not exceed 18 acres. Then additional profit is maximized by maximizing acres of corn, which can be at most half the number of acres of pumpkins, hence 9 acres.
So profit is maximized for 18 acres of pumpkins and 9 acres of corn.
Maximum profit is $360·18 +$225·9 = $8505.
I'm pretty sure the answer is
<span>B. y = 6x
C. y = x2 - 2</span>
The firs term
A(1)=-6+(1-1)(6)
A(1)=-6+(0)(6)
A(1)=-6
The fourh term
A(n)=-6+(n-1)(6)
A(4)=-6+(4-1)(6)
A(4)=-6+(3)(6)
A(4)=-6+18
A(4)=12
The tenth term
A(10)=-6+(10-1)(6)
A(10)=-6+(9)(6)
A(10)=-6+54
A(10)=48
Answer:
D. -6,12,48