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3 years ago

Consider function f. f(x)=√7x-21. place the steps for finding f^-1(x) in the correct order.

Mathematics

1 answer:

poizon [28]3 years ago

6 0

Answer: f 1 2 3 4 5 6

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€ 7

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Step-by-step explanation:

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A sports store sold a total of 59 footballs and soccer balls last weekend. Soccer balls cost $12 and footballs costs $18. If tot

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3 years ago

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Look at the steps used to solve the equation below . Which mathematical property justifies the work between steps #3 and 4 step#

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2 years ago

Write the equation of the circle in standard form: Center (7,0) R=1

Mice21 [21]

Answer:

$(x-7)^2+y^2=1$

Step-by-step explanation:

Hi there!

Equation of a circle: $(x-h)^2+(y-k)^2=r^2$ where the circle is centered at (h,k) and the radius is r

1) Plug in the given center (7,0)

$(x-7)^2+(y-0)^2=r^2\\(x-7)^2+y^2=r^2$

2) Plug in the radius (1)

$(x-7)^2+y^2=1^2\\(x-7)^2+y^2=1$

I hope this helps!

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3 years ago

Because the graph below is misleading, which magazine appears to have about four times the circulation of Circuitry Today?

OverLord2011 [107]

I think the answer is b

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2 years ago

Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

erik [133]

Answer-

2 is the upper limit for the zeros.

Solution-

The given function f(x) is,

$2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

For calculating the zeros,

$\Rightarrow f(x)=0$

$\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

$\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0$

$\Rightarrow 2x^3(x-2)-3x^2(x-2)-2x(x-2)+3(x-2)=0$

$\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0$

$\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0$

$\Rightarrow (x-2)(x^2-1)(2x-3)=0$

$\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0$

$\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0$

$\Rightarrow x=2,\ x=-1,\ x=1,\ x=\frac{3}{2}$

From all the 4 roots, it can be obtained that 2 is the greatest zero.

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3 years ago