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aksik [14]
4 years ago
12

Need help on math question​

Mathematics
1 answer:
andreev551 [17]4 years ago
8 0

Answer:

<h2>y = 4.5</h2>

Step-by-step explanation:

\dfrac{15}{y}=\dfrac{40:4}{12:4}\\\\\dfrac{15}{y}=\dfrac{10}{3}\qquad\text{cross multiply}\\\\10y=(15)(3)\\\\10y=45\qquad\text{divide both sides by 10}\\\\\dfrac{10y}{10}=\dfrac{45}{10}\\\\y=4.5

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Type the correct number to complete each ratio table
ohaa [14]

Answer:

15

Step-by-step explanation:

Jackie would've washed 15 cars, since multiplying 2 x 5 = 10, so you'd have to multiply 3 by 5 to get the amount of cars Jackie washed if Michael washed 10.

4 0
3 years ago
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PLEASE HELP! please help!!! omgggg
anzhelika [568]

Answer:

2nd option because the number next to the x is the slope (3) and the added number is your intercept (4)

Step-by-step explanation:

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3 years ago
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Tom is applying for a visa.
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Answer:

100

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4 0
3 years ago
X varíes directly with y and z. X =1200 when y =20 and z=30 find x when y=10 and z=20
Naya [18.7K]

Answer:

Value of x = 400

Step-by-step explanation:

Joint variation states that describes a situation where a variable depends on two (or more) other variables, and varies directly with some of them.

Given: x varies directly with y and  z.

i.e x \propto y and x \propto z

then we have the joint variation as;

x = k yz ......[1] where k is the constant variation.

Substitute the value of x =1200 when y =20 and z = 30 to solve for k;

1200 = k (20)(30)

Simplify:

1200 = 600k

Divide both sides by 600 we get;

k = 2

Now, substitute k =2 , y =10 and z = 20 to find x;

Using [1] we have;

x = 2 \times (10)(20) = 2 \times 200

Therefore, the value of x is, 400



7 0
3 years ago
Read 2 more answers
Involves sine/cosine rules
katen-ka-za [31]

Answer:

44.47 cm² (nearest hundredth)

Step-by-step explanation:

Area of ΔABC = 1/2 x base x height

⇒ 21 = 1/2 x 7 x BC

⇒ BC = 6 cm

Pythagoras' Theorem: a² + b² = c²

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

⇒ AB² + BC² = AC²

⇒ 7² + 6² = AC²

⇒ AC² = 85

⇒ AC = √85 cm

Cosine rule to find length AD:

      c² = a² + b² - 2 ab cosC

⇒ DC² = AD² + AC² - 2(AD)(AC)cos(DAC)

⇒ 9.2² = AD² + (√85)² - 2(AD)(√85)cos 73°

⇒ AD²  - 5.39106...AD + 0.36 = 0

⇒ AD = 5.323442445, 0.06762541414

⇒ AD = 5.323442445

Area of a triangle ADC: (1/2)absinC

(where a and b are adjacent sides and C is the angle between them)

⇒ area = (1/2) × AC × AD × sin(DAC)

⇒ area = (1/2) × √85 × 5.323442445 × sin(73°)

⇒ area =23.4675821... cm²

Area of quadrilateral = area of ΔABC + area of ΔADC

                                   = 21 + 23.4675821...

                                   = 44.47 cm² (nearest hundredth)

4 0
2 years ago
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