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Anon25 [30]
3 years ago
13

PLEASE HELP! please help!!! omgggg

Mathematics
2 answers:
anzhelika [568]3 years ago
5 0

Answer:

2nd option because the number next to the x is the slope (3) and the added number is your intercept (4)

Step-by-step explanation:

AURORKA [14]3 years ago
5 0

answer:

the secound one :)

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In a weekly lottery, ten ping-pong balls numbered 0 to 9 are placed in each of six containers, and one ping-pong ball is drawn f
sukhopar [10]
He will have a 1/531,441 chance of winning next week.

There are 10 balls in each container; for 6 containers, this gives us 10^6 = 1,000,000.  There is 1 correct combination of balls, so his chance the first week is 1/1,000,000.

The second week, 1 ball is removed from each container; this will give us 9^6 = 531,441 chances.  There is 1 correct combination, so he will have a 1/531,441 chance of winning.
6 0
3 years ago
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Please answer this now in two minutes
Firlakuza [10]

Answer:

x = 6.6

Step-by-step explanation:

Data obtained from the question include the following:

Angle X = 15°

Angle Y° = 23°

Side y = 10

Side x =..?

The value of side x can be obtained by using the sine rule as shown below:

x/Sine X = y/Sine Y

x/Sine 15 = 10/Sine 23

Cross multiply

x × Sine 23 = 10 × Sine 15

Divide both side by Sine 23

x = (10 × Sine 15) / Sine 23

x = 6.6

Therefore, the value of x is 6.6.

7 0
3 years ago
Question 1 (1 point)
taurus [48]

Answer:

question no 1:slope=5

Step-by-step explanation:

let(x=5andy=8)(a=7andb=18)

now

slope=(b-y)/(a-x)=(18-8)/(7-5)=5

5 0
3 years ago
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A transformation is shown in the diagram. ∠A  ∠A' and ∠C ∠C' Which transformation is shown in the figure? ΔABC was dilated to fo
Ivenika [448]

Answer:

the correct option is C

Step-by-step explanation:

6 0
3 years ago
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Find cot θ if csc θ = negative square root of thirty seven divided by six and tan θ > 0.
Ket [755]
You can use the trigonometric identity  1+\cot^2{x}=\csc^2{x}.

1+\cot^2{\theta}=(\frac{-\sqrt{37}}{6} )^2 \\ 1+\cot^2{\theta}=\frac{37}{36} \\ \cot^2{\theta}=\frac{1}{36} \\
\cot{\theta}=\frac{1}{6}

The requirement that \tan{\theta}\ \textgreater \ 0 eliminates -1/6 from being another solution.
6 0
3 years ago
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