1-When you have a the logarithm given in the problem above, you can solve it by using the correct properties for logaritms.
2- The students could solve it as below:
<span>log4(2x-12)=3
4^[</span> log4(2x-12)]=4^3
3- By definition a^log(x)=x, therefore,
2x-12=4^3
2x-12=64
4- Now, the students can solve for x:
x=38
The first step is incorrect, because the term on the right member must be 4^3.
Answer:
freak i wish i could help
Step-by-step explanation:
Answer: Letter B)
A=πr2
d=2r
A=1
4πd2=1
4·π·162≈201.06193
Step-by-step explanation:
Hope this Helps! : )
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Answer:
If a≠0, x=
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Step-by-step explanation:
If a=0 then ax+7=3 then 0+7=3 then 7=3 impossible.
If a≠0 then ax+7=3 ⇔ ax=3-7 ⇔ ax= -4 ⇔ x= -4/a.
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