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Nonamiya [84]
3 years ago
15

❤️❤️anyone know how to do this

Mathematics
1 answer:
Xelga [282]3 years ago
4 0
C because (-4-3)=7 and (8-5)=3 so it would be (7,3)
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A rectangle has dimensions 3x-1 and x+6. Write an expression for the area of the rectangle as a polynomial in standard form
WITCHER [35]

Answer:

the area product is simply (3x+5).(x+7 which can multiply if desired to obtain highlight3x/2+ 26x + 35.

You can use Completion of the Square on the trinomial product to put this trinomial into standard form. You would want this form to be like (x-h)2 +k.

7 0
3 years ago
What is the angle of rotation of the image?<br>A. 60°<br>B. 90°<br>C.120°<br>D. 180°<br>​
lisov135 [29]

Answer:

It would be great if you would provide the image itself. I will totally answer your question.

4 0
3 years ago
A dealer bought a product for 25$ sold it for 26$, bought it back for 27$, and sold it for 28$.
Ronch [10]

He had a profit of $2.  Made a $1 each time he sold it.

3 0
3 years ago
Read 2 more answers
From the observation deck of a skyscraper, Harper measures a 45^{\circ} ∘ angle of depression to a ship in the harbor below. If
Evgesh-ka [11]

The horizontal distance between the base of the skyscraper to the ship is 1145 feet.

Data;

  • Angle = 45 degree
  • Observation deck (adjacent) = 1145 ft
  • horizontal distance (opposite) = x

<h3>Trigonometric Ratios</h3>

Using trigonometric ratios, we have the value of adjacent and angle, we can easily use tangent of the angle to find the horizontal distance

tan\theta = \frac{opposite}{adjacent}

Substitute the values into the equation and solve

tan45 = \frac{x}{1145}\\ x = 1145tan45\\x = 1145ft

The horizontal distance between the base of the skyscraper to the ship is 1145 feet.

Learn more on trigonometric ratio here;

brainly.com/question/4326804

5 0
2 years ago
If Acot theta + Bcot theta =4 and
geniusboy [140]

Answer is: B

Step-by-step explanation: correct answer is B

b  

2

−a  

2

 

Given, acotθ+bcscθ=p

           bcotθ+acscθ=q

⇒p  

2

−q  

2

=(p−q)(p+q)

                   =[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]

                   =[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]

                   =(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)

                   =(a  

2

−b  

2

)(cot  

2

θ−csc  

2

θ)

                   =(−1)(a  

2

−b  

2

)[∵csc  

2

θ−cot  

2

θ=1]

                   =(b  

2

−a  

2

)

7 0
2 years ago
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