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Tems11 [23]
3 years ago
14

Please help me with this

Mathematics
1 answer:
Artemon [7]3 years ago
4 0

If 182 is 20% f the first floor, F, then the first floors area is 910 square feet.

<span> You know that 182 is 20% of F. So, what you do first to figure out how many times you need to multiply 182 is divide 1 with 0.2 (0.2=20%)</span>

<span>1/0.2=5  </span>

Check

5x0.2=1

Now that you’ve figured that out, you can say that 182 is equal to one-fifth of F, and to get the whole floor you can times 182 by 5.

182x5=910 square feet. (910=five-fifths=equals the whole floor/1)

<span>So, the square area of the floor, F,  is 910 .</span>

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What is the root of the polynomial equation x(x-2)(x+3) = 18? Use a graphing calculator and a system of equations.
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Answer:

  x = 3

Step-by-step explanation:

The equation can be rewritten to make use of the graphing calculator's ability to identify function zeros:

  x(x -2)(x +3) -18 = 0

The attached shows x = 3 is the only real solution.

_____

We're not sure what "system of equations" is intended. Perhaps it is ...

  y = 18

  y = x(x -2)(x +3)

To create the expression we graphed, we effectively subtracted the first equation from the second.

3 0
3 years ago
Tim and sue share a small pizza. Tim eats 2/3 of the pizza. sue eats half as much pf the pizza as time doe. what fraction of the
boyakko [2]

Answer:

Sue eats 1/3 of the whole pizza

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
X/5 - 12 = -8 x=? what​
lutik1710 [3]
X = 20

If you multiply both sides by 5 to get rid of the fraction ( x - 60 = -40 ) the answer would become clear.
4 0
3 years ago
consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where
boyakko [2]

Answer:

a)X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

b)Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

Step-by-step explanation:

From the question we are told that

The Function

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

Generally the differentiation of function f(x) is mathematically solved as

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

f(x)=\frac{x^3+x^2+5x+1}{x^2}

Therefore

f'(x)=\frac{x^2+10x+3}{x^4}

Generally critical point is given as

f'(x)=0

\frac{x^2+10x+3}{x^4}=0

x=-5 \pm\sqrt{22}

Generally the maximum and minimum x value for critical point is mathematically solved as

f'(-5 \pm\sqrt{22})

Where

Maximum value of x

f'(-5 +\sqrt{22})

Minimum value of x

f'(-5 +\sqrt{22})

Therefore interval of increase is mathematically given by

f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})

f(x)

Therefore interval of decrease is mathematically given by

(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)

Generally the second differentiation of function f(x) is mathematically solved as

f''(x)=\frac{2(x^2+15x+6)}{x^5}

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f''(x)=0

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Therefore inflection points is given as

x=\frac{1}{2} (-15 \pm \sqrt{201}

f''(x)>0,\frac{1}{2}(-15-\sqrt{201})

a)Generally the concave upward interval X is mathematically given as

X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

f''(x)

b)Generally the concave downward interval Y is mathematically given as

Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

5 0
3 years ago
Decide whether y is a function of x.<br> y=-3x-4
Nataly [62]
Yes, for every value of x, there is only one value of y. This means that y is a function of x.
4 0
3 years ago
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