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NeTakaya
3 years ago
9

Point-Slope Form: y - 5= 3(x- 1) Standard Form: ​

Mathematics
2 answers:
alexira [117]3 years ago
4 0
The answer is Y= 3x +2
Angelina_Jolie [31]3 years ago
3 0

Step-by-step explanation:

y - 5 = 3(x - 1)

y - 5 = 3x - 3

3x - y = -2.

The standard form is 3x - y = -2.

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A marketing research firm would like to survey undergraduate and graduate college students about whether or not they take out st
neonofarm [45]

Answer:

Objective Minimize 10x1 +15x2 + 12x3+18x4+15x5+ 21x6

The central total cost $ 17586 due to the number of central undergraduate students 1458 is very high.

The total minimum cost would $ 17586 +$260+ $300= $ 18146

Step-by-step explanation:

Let

X1 = # of undergraduate students from the East region,

X2 = # of graduate students from the East region,

X3 = # of undergraduate students from the Central region,

X4 = # of graduate students from the Central region,

X5 = # of undergraduate students from the West region, and

X6 = # of graduate students from the West region.

Then  the cost functions are

y1= 10x1 +15x2

y2= 12x3+18x4

y3= 15x5+ 21x6

According to the given conditions

The constraints are

x1 +x2 + x3+x4+ x5+ x6 ≥ 1500------- A

15X2 +18X4+21X6 ≥ 400---------B

21X6 ≥ 100

X6 ≥ 100/21

X6 ≥ 4.76

Taking

X6= 5

10X1 ≤ 500

X1 ≤ 500/10

X1≤ 5

18X4 ≥ 75

X4 ≥ 75/18

X4 ≥ 4.167

Taking

X4= 5

Putting the values

15X5+ 21X6 ≥ 300

15X5+ 21(5) ≥ 300

15X5+ 105 ≥ 300

15X5 ≥ 300-105

15X5 ≥ 195

X5 ≥ 195/15

X5 ≥ 13

Putting value of X6 and X4 in B

15X2 +18X4+21X6 ≥ 400

15X2 +18(5)+21(5) ≥ 400

15X2 +195 ≥ 400

15X2  ≥ 400-195

15X2  ≥ 205

X2  ≥ 205/15

X2  ≥ 13.67

Taking X2= 14

Now putting the values in the cost equations to check whether the conditions are satisfied.

y1= 10x1 +15x2

y1= 10 (5) + 15(14)= 50 + 210= $ 260

y3= 15x5+ 21x6

y3= 15 (13) + 21(5)

y3= 195+105= $ 300

x1 +x2 + x3+x4+ x5+ x6 ≥ 1500

5+14+x3+5+13+5≥ 1500

x3≥ 1500-42

x3≥ 1458

y2= 12x3+18x4

y2= 12 (1458)  + 18 (5)

y2= 17496 +90

y2= $ 17586

The cost can be minimized if the number of students from

                                 Undergraduate         Graduate

East Region              X1≤ 5                            X2  ≥ 13.67

Central                      X3≥ 1458                   X4 ≥ 4.167

West                          X5 ≥ 13                          X6 ≥ 4.76

This will result in the required number of students that is 1500

Constraints:

East Undergraduate must not be greater than 5

East Graduate must not be less than 13

Central Undergraduate must  be greater than 1458

Central Graduate must  be greater than 4

West Undergraduate must  be greater than 13

West Graduate must  be greater than 4

The central total cost $ 17586 due to the number of central undergraduate students 1458 is very high.

The east region has a least cost of $260 and west region has a cost of $300.

The total minimum cost would $ 17586 +$260+ $300= $ 18146

6 0
3 years ago
Help please!!!!!!!!!!!!!!!
Likurg_2 [28]
First, find the area of the whole square.

Area= Base times height= 48 times 96 = 4608

Next, find the area of ONE circle. The diameter is 12, so the radius would be 6

A=πr sqaured= 3.14 times 6 squared = 113.04

Next multiply by 3, since there are 3 circles.

113.04 times 3 =339.12

Subtract this value from the total area (4608)

4608-339.12=4268.88

ANSWER: 4268.88

8 0
3 years ago
The London theater offers child tickets at 10$each and adult tickets at 20$ each.Mrs burham buys 34 tickets at a total cost of 5
kirill115 [55]

Answer:

A+C=34

10C+20A=570

4 0
2 years ago
I asked this earlier and got no answer. Will give brainliest
Virty [35]
The area of a square is

s • s

We can also write this as

s^2

So, for any side length “s”, we can make a function, A(s), such that

A(s) = s^2

Now that we have a quadratic equation for the area of a square, let’s go ahead and solve for the side lengths of a square with a given area. In this case, 225 in^2

225 = s^2

Therefore,

s = sqrt(225)

s = 15

So, the dimensions are 15 x 15 in

6 0
3 years ago
One cubic foot of chemical weighs 80 pounds. How many pounds of the chemical can a container with the dimensions shown hold
Ierofanga [76]

Answer:

yes

Step-by-step explanation:

6 0
3 years ago
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