small biomolecule that serves as a building block for polymers. This is correct
A Burr hole.
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The smallest bone in the human body is the stapes bone, located in the ear.
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The answer is <span>A. p2 = 0.36, 2pq = 0.48, q2 = 0.16.
</span>
Let's first distinguish alleles frequencies from genotypes frequencies:
p - a frequency of R allele,
q - a frequency of r allele,
p² - a frequency of RR genotype,
2pq - a frequency of Rr genotype,
q² - a frequency of rr genotype.
<span>The gene frequency of allele r changes from 0.38 to 0.40, thus:
</span>q = 0.40
Now, we will implement this in the following equation:
p + q = 1
If q = 0.40, then:
p + 0.40 = 1
⇒ p = 1 - 0.40
⇒ p = 0.60
Now, the frequencies of both alleles are know and it is easy to calculate the <span>genotype frequencies:
-</span> the frequency of RR genotype: p² = 0.60² = 0.36
- the frequency of Rr genotype: 2pq = 2 · 0.60 · 0.40 = 0.48
- the frequency of rr genotype: q² = 0.40² = 0.16
Therefore, the new genotype frequencies in that population are <span>p2 = 0.36, 2pq = 0.48, q2 = 0.16.</span>
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