If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
Answer:
1.14 s
Step-by-step explanation:
Time, 
Here, d is the distance and s is the speed/velocity
Since we're given the velocity, s as 28 ft/s and the distance between the position of the rocket and ground as 32 ft then

Therefore, it needs 1.14 seconds
Answer:
minus 5
Step-by-step explanation:
I think so it might be not a correct answer