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astra-53 [7]
3 years ago
14

A toy rocket is lunch vertically upward from ground level in into velocity of one 28 ft./s how long will it take for the rocket

to return to the ground when is the rocket 32 feet above ground
Mathematics
2 answers:
Ad libitum [116K]3 years ago
5 0

<em>Note: As you missed to mention the given equation for t seconds and height h, so I am taking a sample equation h(t) =-16t² + 28t  + 40. So, I am explaining your question based on this equation, which would anyways clear your query. </em>

Answer:

It will take <em>2 seconds</em> for the rocket to return to the ground when is the rocket 32 feet above ground.

<u><em>Note: Sample equation h(t) =-16t² + 28t  + 40 was used to solve this problem, as you had not mentioned the equation.</em></u>

Step-by-step explanation:

To determine:

How long will it take for the rocket to return to the ground when is the rocket 32 feet above ground?

<em>Information Fetching and solution steps:</em>

  • Initial Velocity = 28 ft/s
  • The equation for height h and second t is <em>h(t) = -16t² + 28t +40</em>

<em>So, </em>

Let us consider the equation <em>h(t) = -16t² + 28t + 40</em>

32 = -16t² + 28t + 40

To find out how long will it take for the rocket to return to the ground when is the rocket 32 feet above ground, plug in h(t) = 32ft, rearrange into quadratic form, and solve:

32 = -16t² + 28t + 40

0 = -16<em>t² + 28t + 8</em>

Step 1: Factor right side of equation

0 = −4(4t + 1)(t − 2)

−4(4t + 1)(t − 2) = 0

Step 2: Set factors equal to 0

4t + 1 = 0 or t − 2 = 0

t = -1/4 or t = 2

As t can not be negative, so t = 2 seconds.

Hence, it will take 2 seconds for the rocket to return to the ground when is the rocket 32 feet above ground.

<em />

<em>Keywords: time, height, velocity</em>

<em> Learn more time and height measure from brainly.com/question/1580756</em>

<em> #learnwithBrainly</em>

pentagon [3]3 years ago
4 0

Answer:

1.14 s

Step-by-step explanation:

Time, t=\frac {d}{s}

Here, d is the distance and s is the speed/velocity

Since we're given the velocity, s as 28 ft/s and the distance between the position of the rocket and ground as 32 ft then

t=\frac {32}{28}=1.142857143\approx 1.14 s

Therefore, it needs 1.14 seconds

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