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Dafna11 [192]
4 years ago
6

A suitcase is a rectangular prism whose dimensions are 1 &1/4 feet by 1 & 3/4 feet by 1 & 1/4 feet.Find the volume o

f the suitcase.
ANSWER THIS PLEAAAAAAASSSSS

Mathematics
2 answers:
HACTEHA [7]4 years ago
8 0

Answer:

V=2\frac{47}{64}ft^{3}

Step-by-step explanation:

The volume of a rectangular prism is defined as

V=l \times w \times h

Where l is length, w is width and h is height.

In this case, the dimensions are

1\frac{1}{4}ft, 1\frac{3}{4}ft and 1\frac{1}{4}ft.

First, we need to transform all mixed numbers into fractions.

1\frac{1}{4}ft =\frac{5}{4}ft

1\frac{3}{4}ft=\frac{7}{4}ft

So, using the formula

V=l \times w \times h=\frac{5}{4}ft \times \frac{7}{4}ft \times \frac{5}{4}ft=\frac{175}{64}ft^{3}\\V=2\frac{47}{64}ft^{3}

Therefore, the volume of the suitcase is V=2\frac{47}{64}ft^{3}

PolarNik [594]4 years ago
4 0
1 1/4=5/4
1 3/4=7/4
v=5/4*5/4*7/4=175/64feet^3
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-----------------------------\\\\
\cfrac{4xy}{mn^5}\implies \cfrac{4xy}{1}\cdot \cfrac{1}{m^1}\cdot \cfrac{1}{n^5}\implies 4xym^{-1}n^{-5}

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5 0
3 years ago
Find the value of b.
Nesterboy [21]

Answer: 230^{\circ

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

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  3. \angle BAO \cong \angle BCO (right angles are congruent)

Therefore, we know \triangle ABO \cong \triangle CBO by HL.

Thus, by CPCTC,

\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}

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Suppose that the sum of the three vectors u, v, and w shown in the figure is the zero vector. If w = 10 find u and v.
tangare [24]

a. The value of v is 9.2

b. The value of u is 9.9

<h3>What are vectors?</h3>

Vectors are physical quantities that have both magnitude and direction

<h3>How to find the value of vectors u and v?</h3>

Since we have vectors

  • u at 70° to the x-axis
  • v at 47° to the x-axis and
  • w = 10 at 15° to the x-axis,

We resolve them into component form

So, u = -(ucos70°)i - (usin70°)j

u = -(0.3420u)i - (0.9397u)j

v = -(vcos47°)i + (vsin47°)j

v = -(0.6820v)i - (0.7314v)j

w = (wcos15°)i + (wsin15°)j

w = (0.9659w)i + (0.2588w)j

w = (9.659)i + (2.588)j

Since the sum of the three vectors is zero, we have that

u + v + w = 0

u + v = -w

So,

-(0.3420u)i - (0.9397u)j + [-(0.6820v)i - (0.7314v)j] = -[(9.659)i + (2.588)j]

-(0.3420u)i - (0.9397u)j -(0.6820v)i - (0.7314v)j = -(9.659)i - (2.588)j]

-(0.3420u)i -(0.6820v)i - (0.9397u)j - (0.7314v)j = -(9.659)i - (2.588)j]

-[0.3420u + 0.6820v]i - [0.9397u + 0.7314v]j = -(9.659)i - (2.588)j

Equating i components, we have

-[0.3420u + 0.6820v]i = -9.659i

0.3420u + 0.6820v = 9.659

Dividing through by 0.3420. we have

u + 1.994v = 28.242 (1) and

Also, equating j components, we have

- [0.9397u + 0.7314v]j = -2.588j

0.9397u + 0.7314v = 2.588  

Dividing through by 0.9397 we have

u + 0.778v = 2.754 (2)

<h3>a. The value of v</h3>

Subracring equation (2) from(1),we have

u + 1.994v = 28.242 (1)

-

u + 0.778v = 2.754 (2)

2.772v = 25.488

v = 25.488/2.772

v = 9.19

v ≅ 9.2

The value of v is 9.2

<h3>b. The value of u</h3>

Substituting v into (1), we have

u + 1.994v = 28.242 (1)

u + 1.994(9.19) = 28.242

u + 18.325 = 28.242

u = 28.242 - 18.325

u = 9.917

u ≅ 9.9

The value of u is 9.2

Learn more about vectors here:

brainly.com/question/25705666

#SPJ1

8 0
2 years ago
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