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OlgaM077 [116]
3 years ago
8

What period did ice-age mammals first appear?

Biology
1 answer:
antiseptic1488 [7]3 years ago
6 0

Answer:

Ice Age mammals first appeared 18,000 years ago... during the Ice Age lol

Hope this helps

Explanation:

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When Mendel crossed a plant homozygous for round seeds to another plant homozygous for wrinkled seeds, he found that all the pro
deff fn [24]

Answer:

a. The allele for round seeds is dominant to the allele for wrinkled seeds.

Explanation:

Mendel found that when two pure breeding plants that differ from each other with respect to one genetic trait are crossed, all the progeny express the phenotype of one parent. The phenotype of the other parent is not expressed in the progeny. He concluded that the genetic trait that is expressed in the F1 generation is dominant over the other which is masked in this generation.

A cross between pure breeding plants for round seeds and the wrinkled seeds obtained all the round seeded progeny. This meant that the phenotype "round" was dominant over the phenotype "wrinkled". If the allele "R" gave round phenotype and the allele "r" imparted wrinkled phenotype, the allele "R" was dominant to the "r".

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Three days ago yesterday was the day before tuesday. what day will it be tomorrow
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HELP FAST ASAP PLEASE
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The answer would be letter a
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If A/A ⋅ B/B is crossed with a/a ⋅ b/b and the F1 is testcrossed, what percentage of the testcross progeny will be a/a ⋅ b/b if
Alex787 [66]

Answer:

a) 25%; b) 50%; c) 45%; d) 38%

Explanation:

<h3 /><h3>a) Unlinked genes</h3>

A/A B/B X a/a b/b

F1: A/a B/b

Testcross A/a B/b X a/a b/b

The homozygous recessive individual only produces <em>ab</em><em> </em>gametes.

The F1 produces four types of gametes (each of them with a frequency of 1/4):  <em>AB</em>, <em>Ab</em>, <em>aB </em>and <em>ab</em>.

25% of the progeny will be a/a b/b.

<h3>b) Completely linked genes</h3>

AB/AB X ab/ab

F1: AB/ab

Testcross AB/ab X ab/ab

The F1 produces only two types of gametes, the parentals (each of them with a frequency of 1/2):  <em>AB</em> and <em>ab</em>.

50% of the progeny will be ab/ab.

<h3>c) 10 m.u. apart</h3>

AB/AB X ab/ab

F1: AB/ab

Testcross AB/ab X ab/ab

The F1 produces four types of gametes, the parentals <em>AB</em> and <em>ab </em>and the recombinants <em>Ab</em> and <em>aB</em>.

Since the genes are 10mu apart, 10% of the produced gametes will be recombinant and 90% will be parentals. Since there are two types of parental gametes, each of them has a frequency of 45%.

45% of the progeny will be ab/ab.

<h3>d) 24 m.u. apart</h3>

This is very similar to c).

Since the genes are 24mu apart, 24% of the produced gametes will be recombinant and 76% will be parentals. Since there are two types of parental gametes, each of them has a frequency of 38%.

38% of the progeny will be ab/ab.

5 0
3 years ago
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