Draw two lines that never intersects and those are parallel line. A compass and straightedge helps you make the lines straight.
Answer:
(B , D) = (-2,5)
Step-by-step explanation:
The given quadratic expression is
![3x^{2} -x-10](https://tex.z-dn.net/?f=3x%5E%7B2%7D%20-x-10)
compare the given expression with ![ax^{2} +bx+c](https://tex.z-dn.net/?f=ax%5E%7B2%7D%20%2Bbx%2Bc)
so we have ![a = 3 , b = -1 ,c = -10](https://tex.z-dn.net/?f=a%20%3D%203%20%2C%20b%20%3D%20-1%20%2Cc%20%3D%20-10)
now
and ![b= -1](https://tex.z-dn.net/?f=b%3D%20-1)
we need to find two numbers such that their product is -30 and sum is -1
-6 and 5 are such numbers
so we have
![3x^{2} -6x+5x-10](https://tex.z-dn.net/?f=3x%5E%7B2%7D%20-6x%2B5x-10)
grouping first two terms and last two terms
![(3x^{2} -6x)+(5x-10)](https://tex.z-dn.net/?f=%283x%5E%7B2%7D%20-6x%29%2B%285x-10%29)
factor out 3x from first two terms and 5 from last two terms
( factor out (x-2))
![(x+(-2))(3x+5)](https://tex.z-dn.net/?f=%28x%2B%28-2%29%29%283x%2B5%29)
hence B =-2 and D= 5
(B,D)= (-2,5)
1. Integers numbers are defined as the set of numbers that is formed by Positive numbers, which are also called "Natural numbers"; Negative numbers (They are less than zero) and zero (This has no sign). This set is represented with the letter "Z". Therefore: Z={...-2, -1, 0, 1, 2 ...}.
2. So, if 12 is added to the square of a positive integer, you can write the following the expression:
12+x²=133
3. You can obtain the value of the positive integer "x", by clearing it. Then, you have:
12+x²=133
x²=133-12
x=√(133-12)
x=√121
x=11
Therefore, the positive integer is: 11
<span> x + 1
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3x • (x - 10)<span>2</span></span>