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ki77a [65]
3 years ago
6

Write a function for the situation. Is the graph continuous or discrete? A movie store sells DVDs for $11 each. What is the cost

, C, of n DVDs?
A. C = 11 + n; discrete
B. C = 11n; continuous
C. C = 11 + n; continuous
D. C = 11n; discrete
Mathematics
1 answer:
Goshia [24]3 years ago
7 0
B: because 11 times N will give you how much your cost would be . Example: 11*2= $22 if you bought 2 cds it would be $22. and its continuous cause youre going up at a constant rate.
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What is the gradient of the graph shown
Keith_Richards [23]

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Answer:

  3

Step-by-step explanation:

The gradient is the ratio of "rise" to "run". Here, it appears the line crosses the y-axis at y = -1. It appears that it also crosses the grid intersection at (1, 2). This represents a "rise" (change in y) of (2 -(-1)) = 3, for a "run" (change in x) of (1 -0) = 1. Then the gradient is ...

  m = rise/run = 3/1 = 3

The gradient of the graph is 3.

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Step-by-step explanation:

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3 years ago
if two pyramids are similar and the ratio between the lengths of their edges is 2;7 what is the ratio of their volumes? ...?
jok3333 [9.3K]
<span>The answer is 8:343.

</span>We can use Galileo's square cube law to calculate the ratio between two similar pyramids. The law is used to describe the change of the area or the volume of the shape when their dimensions increase or decrease:
\frac{V_1}{V_2} =( \frac{l_1}{l_2} )^{3} \\<span>
</span><span><span> <span> <span> <span> <span> <span> <span> <span> <span> <span> <span> </span></span></span></span></span></span></span></span></span> </span></span> </span>
V₁ and V₂ - volumes of pyramids,
l₁ and <span>l</span>₂ - the edges of pyramids.
<span>
</span>\frac{V_1}{V_2} =( \frac{l_1}{l_2} )^{3} \\ \frac{V_1}{V_2} =( \frac{2}{7} )^{3} \\ \frac{V_1}{V_2} = \frac{2^{3}}{7^{3}} \\ \frac{V_1}{V_2} = \frac{8}{343} \\<span>
</span>
3 0
2 years ago
Read 2 more answers
What should be done to x^2 + 15x in order to create a perfect square?
lana [24]

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2 \\\\[-0.35em] ~\dotfill

\bf x^2+15x+\boxed{?}^2\implies \stackrel{\textit{we know the middle term is}}{2\sqrt{x^2}\cdot \sqrt{\boxed{?}^2}\implies 2x\boxed{?}}\qquad then\qquad 2x\boxed{?}=15x \\\\\\ \boxed{?}=\cfrac{15x}{2x}\implies \boxed{?}=\cfrac{15}{2}\qquad \impliedby \textit{we should add that much \underline{squared}} \\\\[-0.35em] ~\dotfill\\\\ x^2+15x+\left( \cfrac{15}{2} \right)^2\implies \left(x+ \cfrac{15}{2} \right)^2

5 0
3 years ago
3/5 meters per 9 minutes.<br> What is the unit rate in minutes per meter?
shepuryov [24]

Answer:

.06 meters

Step-by-step explanation:

3/5=.6

.6/9=.06

6 0
3 years ago
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