Answer:
a = 133 degrees
b = 78 degrees
Step-by-step explanation:
the top and bottom lines are parallel.
the two sidelines are lines that intercept the top and bottom lines.
as they intercept parallel lines, they actually must have the same angles with them.
so, the 47 degrees inner angle at the bottom line, must be also somewhere at the interception point with the top line. and right, it must be now mirrored the outward angle at the top line. and that means a (the inward angle at the top line) is also the outward angle at the bottom line.
the sum of inward and outward angles at a point must always be 180 degrees.
so, the outward angle of 47 = the inward angle a =
= 180 - 47 = 133 degrees.
similar in the other side.
102 is the inward angle.
the outward angle of that is 180 - 102 = 78 degrees.
and that is also the inward angle b.
b = 78 degrees
The sum if the geometric sequence given by:
an=-2(3)^(n-1)
will be:
when:
n=1
an=-2
when n=2
a2=-6
when n=3
a3=-18
when n=4
a4=-54
when n=5
a5=-162
when n=6
a6=-486
when n=7
a7=-1458
when n=8
a8=-4374
thus the summation of the term will be:
Sn=(-4374+-1458+-486+-162+-54+-18+-6+-2)
Sn=-6560
the answer is -6560
Answer:
B -1/5
you have to follow pemdas first get rid of the parethase which leaves you with 2+3x+6x=-4x+8x+1 then you add what you can do then you get 2+9x=4x+1 then you subtract 2 from both sides and subtract 4x from both sides which leaves you with 5x=-1 then you divide 5 from both sides and get x=-1/5
Step-by-step explanation:
The general equation is y = mx + c...
The given equation is 2x + y = 6
Firstly, move everything on the left except the y to the right.i.e.
y = 6 - 2x
Secondly, rearrange the values on the right to look just like the general equation.
y = -2x + 6
The equation is now in proper general form because it matches the format laid down.
Answer:
Change in sulfur oxide in the air = 
Step-by-step explanation:
Data provided in the question:
Relation between the amount of sulfur oxide in the air and the population as:
S² = 110P² + 20P + 600
Population growth rate, 
= 10 people per month
Now,
change in sulfur oxide with time i.e 
differentiating the given relation with respect to time 't'
we have
= 
+ 20
at P = 100 and = 10 people per month
we have
= 2 × 110 × 100 × 10 + 20
or
= 220020
or
= 
or
Change in sulfur oxide in the air =
