A beetle was running along a number line, Then the bug ran from 28 to 78. What distance did it cover? If this run took the bug 9
1 answer:
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Answer:
<em><u>given </u></em><em><u>:</u></em><em><u>-</u></em>
<em><u>for </u></em><em><u>rectangular</u></em><em><u> </u></em><em><u>part:</u></em><em><u> length</u></em><em><u>=</u></em><em><u>1</u></em><em><u>2</u></em><em><u>i</u></em><em><u>n</u></em><em><u>,</u></em><em><u> breadth</u></em><em><u>=</u></em><em><u>8</u></em><em><u>i</u></em><em><u>n</u></em>
<em><u>for</u></em><em><u> </u></em><em><u>triangular</u></em><em><u> </u></em><em><u>part:</u></em><em><u>base=</u></em><em><u>8</u></em><em><u>i</u></em><em><u>n</u></em><em><u>,</u></em><em><u> </u></em><em><u>height=</u></em><em><u>3</u></em><em><u>i</u></em><em><u>n</u></em>
<em><u>area of the given fig:</u></em>
<em><u>area of the given fig:area of 2 triangles +area of rectangle </u></em>
<em><u></u></em>
Answer:
Answer B) (2 times )
Step-by-step explanation:
Let's start with the person that shook hands more (Dora), so we already know how four of this connections took place See attached image.
step 1:
D is connected to A, B, C, and E
Step 2:
Now proceed with the connections for the second greatest (C who shook hands with 3 people). Notice that C is already connected with D, and can connect with B and with E, but NOT with A (since this person shook hands only once - with D. So C is connected to B, D, and E completing the three handshakes.
step 3: Now just corroborate that B is already connected to two people (C and D). So just count the number of connections that E is left with: 2 handshakes.
