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BabaBlast [244]
3 years ago
10

A movie rental website charges $5.00 per month for membership and $1.25 per movie.

Mathematics
1 answer:
denis-greek [22]3 years ago
4 0
To solve this problem, I would transfer this word problem into an equation with variables.

let the variable m stand for the amount of movies andrew rents.

5.00+1.25m=16.25

Now that we have our equation, we can just solve it like any other equation.
To do this, first, we would subtract 5.00 from both sides, resulting in the equation

1.25m=11.25

Next, we would divide both sides by 1.25, resulting in your final answer

m=9.

This means that Andrew rented 9 movies if his total was 16.25
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A truck driver is driving from Nome, Alaska to Death Valley, California. Because he is traveling between locations with extreme
Andrews [41]

The inequality to represent the temperatures at which the gas in the truck will remain in liquid form is -40 < x < 140

<h3>Part A: The inequality</h3>

Let the temperature of the gas be represented with x.

When the temperature hits −40° F (or below), the gas freezes.

This means that the gas temperature must always exceed −40° F to remain being a liquid

i.e x > −40

Also, when the temperature hits 140° F (or above), the gas evaporates.

This means that the gas temperature must always be less than 140° F to remain being a liquid

i.e x < 140

So, we have:

x > −40 and x < 140

Rewrite as:

-40 < x and x < 140

Combine both inequalities

-40 < x < 140

Hence, the inequality to represent the temperatures at which the gas in the truck will remain in liquid form is -40 < x < 140

<h3>Part B: The description of the graph</h3>

In (a), we have:

-40 < x < 140

The end points of the inequalities use a less than sign.

Less than signs are represented by open circle.

Hence, the graph would use an open circle, and intervals between -40 and 140 would be shaded

<h3>Part C: Would −49° F gas remained in liquid form?</h3>

We have:

-40 < x < 140

The number -49 is not in the range -40 < x < 140

Hence, the gas would not remain in liquid form (in fact, it would freeze because it is less than -40)

Read more about inequalities at:

brainly.com/question/24372553

#SPJ1

8 0
1 year ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
svet-max [94.6K]

Answer:

tan (C) = 2.05

Step-by-step explanation:

Given:

A right angled triangle CDE right angled at ∠D.

Side CD = 39

Side DE = 80

Side CE = 89

We know, from trigonometric ratios that, the tangent of any angle is equal to the ratio of the opposite side to the angle and the adjacent side of the angle.

Therefore, tangent of angle C is given as:

\tan(\angle C)=\frac{DE}{CD}

Plug in the given values and solve for angle C.This gives,

\tan(\angle C)=\frac{80}{39}\\\\\tan(\angle C)=2.051\approx 2.05(Rounded\ to\ nearest\ hundredth)

Therefore, the measure of tangent of angle C is 2.05.

4 0
2 years ago
Suppose the scores of students on an exam are normally distributed with a mean of 244 and a standard deviation of 79. According
Ahat [919]
244 - 165 = 79 . . . . one standard deviation
323 - 244 = 79 . . . . one standard deviation

The range of scores is ±1 standard deviation from the mean. The empirical rule says 
   68% of scores lie in that range.
3 0
3 years ago
the taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km,
Olegator [25]

Answer:

255

Step-by-step explanation:

total cost paid = fixed cost + total variable cost

total variable cost = distance travelled x variable cost per unit

two equations can be derived from the question

a + 10b = 105  equation 1

a + 15b = 155   equation 2

a = fixed cost

b =  variable cost per unit

Subtract equation 1 from 2

5b = 50

b = 10

Substitute for b in equation 1

a + 10(10) = 105

a = 105 - 100 = 5

a = 5

cost of travelling a distance of 25km

5 + 10(25) = 255

3 0
2 years ago
You earn $20 per hour doing landscaping work. Your total earnings depend on the amount of hours you spend landscaping.
lina2011 [118]
20(x)

x=how many hours worked
6 0
2 years ago
Read 2 more answers
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