Answer:
Cos θ = √7/3
Step-by-step explanation:
From the question given above, the following data were obtained:
Sine θ = √2 / 3
Cos θ =?
Recall
Sine θ = Opposite / Hypothenus
Sine θ = √2 / 3
Thus,
Opposite = √2
Hypothenus = 3
Next, we shall determine the Adjacent. This can be obtained as follow:
Opposite = √2
Hypothenus = 3
Adjacent =?
Hypo² = Adj² + Opp²
3² = Adj² + (√2)²
9 = Adj² + 2
Collect like terms
9 – 2 = Adj²
7 = Adj²
Take the square root of both side
Adjacent = √7
Finally, we shall determine the value Cos θ. This can be obtained as follow:
Adjacent = √7
Hypothenus = 3
Cos θ =?
Cos θ = Adjacent / Hypothenus
Cos θ = √7/3
Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.
Let's see if there are anything we missed:
∞
Σ 2^n=1+2+4+8+16+...
n=0
We multiply (2-1) on both sides:
∞
(2-1) Σ 2^n=(2-1)1+2+4+8+16+...
n=0
And we expand;
∞
Σ 2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)
n=0
But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:
∞
Σ 2^n=-1+2(2^n)
n=0
If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.
Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.
Yep, this shows how weird the infinity sign is.
Answer:
An Arc
Step-by-step explanation:
Answer:
165
Step-by-step explanation:
Im not understanding what you are asking
