Help me answer this pls
1 answer:
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To change a decimal to a fraction, we simply "use as many zeros as there are decimals and lose the dot".
say in this case, 0.8 has 1 decimal, so we'll use one zero at the bottom,
say in this case, 0.8 has 1 decimal, so we'll use one zero at the bottom,
A postcard is in the shape of a parallelogram. A parallelogram is a quadrilateral with two pair of parallel sides, opposite sides and opposite angles are equal.
Since, the postcard has an area of 12 square inches.
Since, area of parallelogram =
As area of parallelogram is 12, it means that the product of base and height is 12 square inches.
So, the possible dimensions of postcard are 3 inches and 4 inches and 2 inches and 6 inches.
So, base = 3 inches , height = 4 inches or base = 4 inches , height = 3 inches.
So, base = 2 inches, height = 6 inches or base = 6 inches , height = 2 inches.
Answer:
The probability of using one or the other is 36%
Step-by-step explanation:
For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:
Probability of passing Professor Jones math class = 64% =0,64
P(J) = 0.64
Probabiliry of passing Professor Smith's physics class = 32% =0.32
P(S) = 0.32
Probability of passing both is = 30% = 0.30
P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram
We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:
P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%
If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.
