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2 years ago

Given the perimeter of a square find the length of one side using the appropriate formula

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

8 0

With a square, all you need to do to find the length of one side is to divide the perimeter by 4. If it is the area you are calculating, then you need to find the square root. For that equation the answer is 24.

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Algebra 1 : ordered pairs kinda dont get it

lesantik [10]

Answer:

Option C; 3x - y = -27 and x + 2y = 16

Step-by-step explanation:

1. Let us consider the equation 21x - y = 9. In this case it would be best to keep the equation in this form, in order to find the x and y intercept. Let us first find to y - intercept, for the simplicity ⇒ 21 * ( 0 ) - y = 9 ⇒ y = - 9 when x = 0. Now if we take a look at the first plot of line q, we can see that the x value is -9 rather than the y value, so this equation doesn't match that of line q. This would eliminate the first two options being a possibility.

2. Now let us consider the equation 3x - y = -27. Let us consider the x-intercept in this case. That being said, ⇒ 3x - ( 0 ) = -27 ⇒ 3x = -27 ⇒ x = -9 when y = 0. As we can see, this coordinate matches with one of the coordinates of line q, which might mean that the second equation could match with the equation for line v.

3. To see whether Option 3 is applicable, we must take a look at the 2nd equation x + 2y = 16. Let us calculate the y - intercept here: ( 0 ) + 2y = 16 ⇒ 2y = 16 ⇒ y = 8 when x = 0. Here we can see that this coordinate matches with that of the second coordinate provided as one of the points in line v. That means that ~ Answer: Option C

6 0

3 years ago

A company produces two types of solar panels per year: x thousand of type A and y thousand of type B. The revenue and cost equat

jolli1 [7]

Answer:

7000 type A
6000 type B

Step-by-step explanation:

We assume your equations are intended to be ...

$C(x,y)=x^2-2xy+9y^2+3x-87y-6\\R(x,y)=5x+7y$

Then the profit equation is ...

$P(x,y)=R(x,y)-C(x,y)=5x+7y-x^2+2xy-9y^2-3x+87y+6\\=-x^2+2xy-9y^2+2x+94y+6$

The partial derivatives of profit with respect to x and y are zero when profit is maximized.

∂P/∂x = 0 = -2x +2y +2

∂P/∂y = 0 = 2x -18y +94

Simplifying, these equations are ...

y = x -1
x -9y = -47

Substituting the first into the second gives ...

x -9(x -1) = -47

-8x = -56

x = 7

y = 7 -1 = 6

The company will maximize profit by selling 7000 panels of type A and 6000 panels of type B.

5 0

3 years ago

McDonald's has sold more than a billion hamburgers. If it were possible to eat a hamburger every minute of everyday (day and nig

Stolb23 [73]

500mil is the answer of course

4 0

3 years ago

What is the domain of y=4sin(x)?

stealth61 [152]

Answer:

( − ∞ , ∞ ) { x | x ∈ R }

Step-by-step explanation:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

4 0

3 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago