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zhannawk [14.2K]
3 years ago
13

Is 7 a whole number ​

Mathematics
1 answer:
rusak2 [61]3 years ago
6 0
Yes, it isn’t a fraction, decimal, or mixed number.
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Solve for z.<br> -cz + 62 = tz + 83
kow [346]
This is how I solved it and the answer

4 0
3 years ago
A DVD is being sold for $15.98 this is after a 45% discount what is the pre-discount price.
Yuri [45]

Answer:

$23.17

Step-by-step explanation:

change 45% to a decimal than multiply .45 by $15.98 then add 15.98

4 0
3 years ago
Questions Below. Would Appreciate Help!
kherson [118]

Answer:

The function that could be the function described is;

f(x) = -10 \cdot cos \left (\dfrac{2 \cdot \pi }{3} \cdot x \right ) + 10

Step-by-step explanation:

The given parameters of the cosine function are;

The period of the cosine function = 3

The maximum value of the cosine function = 20

The minimum value of the cosine function = 0

The general form of the cosine function is presented as follows;

y = A·cos(ω·x - ∅) + k

Where;

\left | A \right | = The amplitude = Constant

The period, T = 2·π/ω

The phase shift, = ∅/ω

k = The vertical translation = Constant

Therefore, by comparison, we have;

T = 3 = 2·π/ω

∴ ω = 2·π/3

The range of value of the cosine of an angle are;

-1 ≤ cos(θ) ≤ 1

Therefore, when A = 10, cos(ω·x - ∅) = 1 (maximum value of cos(θ)) and k = 10, we have;

y = A × cos(ω·x - ∅) + k

y = 10 × 1 + 10 = 20 = The maximum value of the function

Similarly, when A = 10, cos(ω·x - ∅) = -1 (minimum value of cos(θ)) and k = 10, we get;

y = 10 × -1 + 10 = 0 = The minimum value of the function

Given that the function is a reflection of the parent function, we can have;

A = -10, cos(ω·x - ∅) = -1 (minimum value of cos(θ)) and k = 10, to get;

y = -10 × -1 + 10 = 20 = The maximum value of the function

Similarly, for cos(ω·x - ∅) = 1 we get;

y = -10 × 1 + 10 = 0 = The minimum value of the function

Therefore, the likely values of the function are therefore;

A = -10, k = 10

The function is therefore presented as follows;

y = -10 × cos(2·π/3·x) + 10

8 0
3 years ago
Aria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there wer
denpristay [2]

Answer:

8,800,000cars

Step-by-step explanation:

Given the initial amount of cars = 80,000,000

If there is 10 % increase in the first year;

Increment = 10% of 80,000,000

Increment = 0.1 * 80,000,000

Increment = 8,000,000

Amount of car in year 2 = 80million + 8million = 88million

Year3;

Amount of car in year 3 = 88,000,000+(10%of88million)

Amount of car in year 3 = 88,000,000+8,800,000

Amount of car in year 3 =96,800,000

Differences in the number of cars = 96,800,000 - 88,000,000

Differences in the number of cars = 8,800,000cars

<em>Hence there are 8,800,000cars in years 3 than year 2</em>

7 0
3 years ago
Brian and Cyril spend a certain amount of money from their money box each month to buy plants.
dimaraw [331]
I feel the answer is function 2 shows a greater rate of change because cyril spends 65 each month and brian spends 18 each month
8 0
3 years ago
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