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3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPP PLSSSSSS

Mathematics

1 answer:

Natasha2012 [34]3 years ago

7 0

Answer:

values of k:

any real number works

Step-by-step explanation:

k^2 is always >=0 so

k^2+96 is always >0

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Suppose that the weights of 5400 registered female Labrador retrievers in the United States are distributed normally with a mean

Maurinko [17]

Answer:

$N= 4543$ Labrador retrievers

Step-by-step explanation:

We know that the mean $\mu$ is:

$\mu = 62.5$

and the standard deviation $\sigma$ is:

$\sigma=2.5$

The probability that a randomly selected Labrador retriever weighs less than 65 pounds is:

$P(X$

We calculate the Z-score for X =65

$Z = \frac{X-\mu}{\sigma}\\\\Z =\frac{65-62.5}{65}=1$

$P(X$

Looking in the table for the standard normal distribution we have to:

$P(Z$ .

Finally the amount N of Labrador retrievers that weigh less than 65 pounds is:

$N = P(X$

$N = 0.8413*5400$

$N= 4543$ Labrador retrievers

6 0

3 years ago

How many numbers between 1 and 100 are divisible by 3 or 2

Zielflug [23.3K]

Answer:

By 3: 33 numbers

By 2: 49 numbers

Both: 66 numbers

4 0

4 years ago

Help me solve this please

Tresset [83]

6v = 5/8+ 7/8
6v= 12/8
6v=6/4 = 3/2
V= (3/2)/6
V=(3/2) • (1/6)
V= 3/12

V = 1/4

3 0

3 years ago

A mixture of alcohol and water contains a total of 60 oz of liquid there are 12 oz of pure alcohol in the mixture was a percenta

OlgaM077 [116]

Answer:

The mixture contains 80% water and 20% alcohol.

Step-by-step explanation:

Given:

Total Amount of mixture = 60 oz

Amount of alcohol in the mixture = 12 oz

We need to find the percentage of water and percentage of alcohol in the mixture.

Solution:

First we will find the amount of water in mixture.

Now we know that;

Total Amount of mixture is equal to sum of Amount of alcohol in the mixture and amount of water in mixture.

so we can say that;

amount of water in mixture = Total Amount of mixture - Amount of alcohol in the mixture

amount of water in mixture = $60-12 =48\ oz$

Now we will find the Percentage amount of water.

Percentage amount of water can be calculated by dividing amount of water in mixture by Total Amount of mixture and then multiplying by 100.

framing in equation form we get;

Percentage amount of water = $\frac{48}{60}\times 100 = 80\%$

Percentage amount of alcohol = $100\%-80\%=20\%$

Hence The mixture contains 80% water and 20% alcohol.

7 0

3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Contact [7]

Answer: a. n= 1068

b. n= 164

Step-by-step explanation:

The formula to find the sample size :

$n=p(1-p)(\dfrac{z^{*}}{E})^2$

, where p=prior population proportion , z* = critical z-value and E = Margin of error.

Here , let p=proportion of computers that use a new operating system.

Given : Confidence level = 95%

i.e. z* = 1.96 [by z-table]

Margin of error : E = 3% =0.03

a. If p is unknown , then we assume p=0.5

Then, $n=(0.5)(1-0.5)(\dfrac{1.96}{0.03})^2=1067.11111\approx1068$

i.e. n= 1068

b. p=0.96

Then, $n=(0.96)(1-0.96)(\dfrac{1.96}{0.03})^2=163.908266667\approx164$

i.e. n= 164.

6 0

3 years ago