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Answer:
The load weight is 2.29 N
Step-by-step explanation:
We note that at equilibrium, the sum of the moment and the sum of forces about a point is zero, therefore, we have;
∑M =0
∑F = 0
The parameters given are;
The distance of the load from the hinge = 35 cm
The distance of the load from the spring balance = 15 cm
The applied force on the spring balance = 4 N↑
The direction of the applied force on the spring balance = Upwards
Let the weight of the load = W↓
The direction of the weight of the load = Downwards
We use downward negative and upward positive coefficients for the forces
We take moment about the hinge as follows;
Sum of moments equals zero gives;
4 × (35 - 15) - W × 35 = 0
∴ 4 × (35 - 15) = W × 35
4 × 20 = W × 35
W = 4 × 20/35 = 2.29 N
The weight of the load = 2.29 N.
Answer:
Step-by-step explanation:
Rearranging your quadratic to standard form, you get ...
16t^2 -4t +d = 0
For the quadratic formula, you have ...
a = 16
b = -4
c = d
so the solution is ...
Answer:
A. Train A begins 1800 miles from Columbus while train B begins 1200 miles from Columbus
B. Train A travels at a constant rate because its graph is a linear equation. Train B does not move until 1pm, when it starts moving towards Columbus at the same speed as train A. I know that trains are traveling at the same speed at a certain interval because they have the same slope at that interval. Because the train was moving at the same speed as train A over a certain interval, Tom is correct.
Step-by-step explanation:
