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3 years ago

How can you show that two objects are proportional with an equation

1 answer:

5 0

The equation has to (or be transformed to) contain one object in the left side and the other object at the right side multiplied by a constant, without an independent term.

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Solve : 1+8n=13+6n help???

ANTONII [103]

1+8n=13+6n
1+8n=13-6n
-6n
1+2n=13
-1 -1
2n=12
2n divided by 2... 12 divided by 2 = 6... n=6

4 0

3 years ago

Read 2 more answers

An airplane spots the floating debris at an angle of depression of 15 degrees. If the plane is at an altitude of 3000. Feet, wha

hodyreva [135]

Answer:

11196.15 km

Step-by-step explanation:

Consider the attached diagram

If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.

Using trigonometry

$Tan \alpha =\frac{Opposite}{adjacent} \\Tan 15 =\frac{3000}{|AB|}$

Cross multiply

|AB|X Tan 15 =3000

|AB| = $\frac{3000}{Tan 15}$ =11196.15 km

Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km

6 0

3 years ago

Plz help I am new to this I would appreciate the help

sammy [17]

Round to the nearest fraction and find a number to divid that go into the top and bottom number

3 0

3 years ago

Add or subtract. Simplify your answer. x+2/x^2−100 + 8/x^2−100

stiv31 [10]

$\dfrac{x+2}{x^2-100}+\dfrac{8}{x^2-100}=\dfrac{x+2+8}{x^2-100}=\dfrac{x+10}{x^2-10^2}\\\\=\dfrac{x+10}{(x+10)(x-10)}=\dfrac{1}{x-10}\to\fbox{B.}\\\\\\The\ domain:\\D:m\neq0\ and\ m\neq-7\\\\\dfrac{1}{m}=\dfrac{2}{m+7}\ \ \ \ |cross\ multiply\\\\2\cdot m=1\cdot(m+7)\\2m=m+7\ \ \ \ |subtract\ "m"\ from\ both\ sides\\\boxed{m=7}$

8 0

3 years ago

Lizzie walked 8/10 mike and billy walked 12/15 mile. Lizzie says they walked the same distance.Do you agree with Lizzie? Explain

Alex_Xolod [135]

Answer:

true they walk the same distance

Step-by-step explanation:

8/10 is equal to 0.8

also 12/15 is also 0.8

therefore walking the same distance

7 0

3 years ago

Read 2 more answers