How can you show that two objects are proportional with an equation

1 answer:

5 0

The equation has to (or be transformed to) contain one object in the left side and the other object at the right side multiplied by a constant, without an independent term.

You might be interested in

What is the volume of the cylinder below?

yulyashka [42]

Answer:

Step-by-step explanation:

v=πr2h

r=(3)²* 5

45π unit³

4 0

2 years ago

If f(x)= x^2 - x+ 1 and f (-1), then the result is

OLEGan [10]

Answer:

Step-by-step explanation:

To solve f(-1), entails to replace x by -1 in the function

f(-1)= (-1)^2 - (-1)+ 1

= 1 + 1 + 1

= 3

6 0

2 years ago

Write in standard form 2+4i over 1+i

Levart [38]

So hmm a conjugate, is pretty much just, the same binomial, but with a different sign in the middle, so, a + b, has a conjugate of a - b
or -a + b, has a conjugate of - a - b, or c - d, has a conjugate of c +d, and so on

anyway, the idea being, to "rationalize" the expression, namely, getting rid of the pesky radical in the denominator

so, we'll multiply the expression by 1, since anything times 1 is just itself

however, bear in mind, that 1, can be a/a, or b/b, or cheese/cheese, or anything/anything

so, we'll multiply the top and bottom of the fraction, by the conjugate of the denominator

anyhow, that said $\bf \cfrac{2+4i}{1+i}\cdot \cfrac{1-i}{1-i}\implies \cfrac{(2+4i)(1-i)}{(1+i)(1-i)}\implies \cfrac{2-2i+4i-4i^2}{1-i^2}\\\\
-----------------------------\\\\
\textit{recall that }i^2=-1\\\\
-----------------------------\\\\
 \cfrac{2-2i+4i-4(-1)}{1-(-1)}\implies \cfrac{2+2i+4}{2}\implies \cfrac{6+2i}{2}\implies \cfrac{6}{2}+\cfrac{2i}{2}
\\\\\\
\boxed{3+i}$