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GuDViN [60]
3 years ago
8

Rolling a fair twelve-sided die produces a uniformly distributed set of numbers between 1 and 12 with a mean of 6.5 and a standa

rd deviation of 3.452. Assume that n twelve-sided dice are rolled many times and the mean of the n outcomes is computed each time.
a. Find the mean and standard deviation of the resulting distribution of sample means for n-49.
The mean of the resulting distribution of sample means is?
The standard deviation of the distribution of sample means is?

b. Find the mean and standard deviation of the resulting distribution of sample means for n = 121.
The mean of the resulting distribution of sample means is?
The standard deviation of the distribution of sample means is?

c. Why is the standard deviation in part a different from the standard deviation in part b?
Mathematics
1 answer:
Alla [95]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that rolling a fair twelve-sided die produces a uniformly distributed set of numbers between 1 and 12 with a mean of 6.5 and a standard deviation of 3.452.

Assume that n twelve-sided dice are rolled many times and the mean of the n outcomes is computed each time.

By central limit theorem we can say the mean of all the n outcomes will follow a normal distribution with mean = 6.5 and std deviation = \frac{3.452}{\sqrt{n} } where n stands for number of samples

Thus we find that std deviation of sample mean called standard error is inversely proportional to square root of sample size.

a) Mean = 6.5 and std deviation = 0.4931

b) Mean = 6.5 and std deviation = 0.332

c) The standard deviation is small in part b because here we divide 3.452 by 11, whereas in b we divided by 7 only.

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Given:

A plane flying a straight course observes a mountain at a bearing of 35° to the right of its course.

The distance between plan and mountain is 10 km.

A short time later, the bearing to the mountain becomes 45°.

Here NM is the distance between the plane from the mountain when the second bearing is taken.

We need to find the measure of NM.

We\text{ know that }\angle INM\text{ and }\angle\text{XNM are supplementary angles.}

The sum of the supplementary angles is 180 degrees.

\angle INM+\angle XNM=180^o\text{Substitute }\angle XNM=45^o\text{ in the equation.}

\angle INM+45^o=180^o

\angle INM=180^o-45^o

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We know that the sum of all three angles of the triangle is 180 degrees.

\angle INM+\angle NIM+\angle INM=180^o\text{Substitute }\angle INM=135^o\text{ and }\angle NIM=35^o\text{ in the equation.}

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