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nadya68 [22]
3 years ago
10

Choose the following which is COMPLETELY correct:

Mathematics
1 answer:
Vlada [557]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Mean = (4+4+5+8+9) / 5

            30 / 5

             6

Median = put them in order and the one in the middle is the median.

                4, 4, <u>5</u>, 8, 9

Mode = the most common

            <u>4, 4</u>, 5, 8, 9

     

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Qualitative graphs are graphs that are used to represent situations that do not necessarily have numerical values. Qualitative graphs represent the essential elements of a situation in a graphical form. For example, Graph A could represent a car that is accelerating at a constant rate.

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Please help as soon as possible. With correct answer and explanation!!!
Roman55 [17]

Answer:  Reflexive Property

<u>Step-by-step explanation:</u>

A side congruent to itself is Reflexive Property.

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Sarah has gone to work for 60 days. On 39 of those days, she arrived at work before 8:30 A.M. On the rest of the days she arrive
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4 0
3 years ago
Two particles move in the xy-plane. At time t, the position of particle A is given by x(t)=5t−5 and y(t)=2t−k, and the position
Ipatiy [6.2K]

Answer:

Part A)  Not collide

Part B)  k = 4

Part C)  Particle B is moving fast.

Step-by-step explanation:

Two particles move in the xy-plane. At time, t

<u><em>Position of particle A:-</em></u>

x(t)=5t-5

y(t)=2t-k

<em><u>Position of particles B:-</u></em>

x(t)=4t

y(t)=t^2-2t+1

Part A)  For k = -6

Position particle A, (5t-5,2t+6)

Position of particle B, (4t,t^2-2t-1)

If both collides then x and y coordinate must be same

Therefore,

  • For x-coordinate:

5t - 5 = 4t    

       t = 5

  • For y-coordinate:

2t+6=t^2-2t-1

t^2-4t-7=0

t=-1.3,5.3

The value of t is not same. So, k = -6 A and B will not collide.

Part B) If both collides then x and y coordinate must be same

  • For x-coordinate:

5t - 5 = 4t    

       t = 5

  • For y-coordinate:

2t-k=t^2-2t-1

Put t = 5

10-k=25-10-1

k=4

Hence, if k = 4 then A and B collide.

Part C)

Speed of particle A, \dfrac{dA}{dt}

\dfrac{dA}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}

\dfrac{dA}{dt}=2\cdot \dfrac{1}{5}\approx 0.4

Speed of particle B, \dfrac{dB}{dt}

\dfrac{dB}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}

\dfrac{dB}{dt}=2t-2\cdot \dfrac{1}{4}

At t = 5

\dfrac{dB}{dt}=10-2\cdot \dfrac{1}{4}=2

Hence, Particle B moves faster than particle A

8 0
3 years ago
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