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3 years ago

How do i solve this? ASAP!

Mathematics

1 answer:

lukranit [14]3 years ago

8 0

Answer:

Similar triangles states the length of the corresponding sides are in proportion.

In a given similar triangles:

Labelled the diagram:

Triangle BAC and triangle DAC are similar.

then;

Corresponding sides:

$\frac{AB}{AD} = \frac{BC}{DC}$

AB = x units , BC = 5 units, AD = 15 units and DC = BD-BC = 8-5 = 3 units

$\frac{x}{15} = \frac{5}{3}$

By cross multiply we get;

$3x = 15 \cdot 5$

Simplify:

$3x = 75$

Divide both sides by 3 we get;

$\frac{3x}{3}=\frac{75}{3}$

Simplify:

x = 25 units

Therefore, the value of x is 25 units.

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If you take 5 quizzes and get scores of 95%, 95%, 80%, 85%, and 75%, how would you find your mean quiz score?

avanturin [10]

Answer:

The answer is C.

Step-by-step explanation:

Remember, to find the mean of some scores, you must add all the scores together, then you must divide by the number of scores you added. In this case, you would divide by four, because you had four numbers you added to gether.

4 0

3 years ago

Can you solve this for me please

Hatshy [7]

Answer:

Graph 1

Step-by-step explanation:

f(x) = __

In this equation (f(2) = 4) the 2 is the x value. All this question is asking is which graph shows a y value of 4 when x is 2.

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3 years ago

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SVETLANKA909090 [29]

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3 years ago

Read 2 more answers

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.

seropon [69]

Answer:

$h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}$

Step-by-step explanation:

1) The Fundamental Theorem of Calculus in its first part, shows us a reciprocal relationship between Derivatives and Integration

$g(x)=\int_{a}^{x}f(t)dt \:\:a\leqslant x\leqslant b$

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

$h(x)=\int_{a}^{x^{2}}\sqrt{5+r^{3}}\therefore h'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left (\int_{a}^{x^{2}}\sqrt{5+r^{3}}\right )\\h'(x)=\sqrt{5+r^{3}}\\Chain\:Rule:\\F'(x)=f'(g(x))*g'(x)\\h'=\sqrt{5+r^{3}}\Rightarrow h'(x)=\frac{1}{2}*(r^{3}+5)^{-\frac{1}{2}}*(3r^{2}+0)\Rightarrow h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}$

3) To test it, just integrate:

$\int \frac{3r^{2}}{2\sqrt{r^3+5}}dr=\sqrt{r^{3}+5}+C$

5 0

3 years ago

Find sin(2x), cos(2x) and tan (2x) from the given information. cot(x)=2/3, x in quadrant I

Usimov [2.4K]

Answer:

1.) 6√13/13

2.) 4√13/13

3.) 3

Step-by-step explanation:

given that cot(x) = 2/3

But cot(x) = 1/tan(x)

Substitutes 1/tan(x) for cot(x)

1/tan(x) = 2/3

Reciprocate both sides

Tan(x) = 3/2 = opposite/adjacent

Use pythagorean theorem to find the hypothenus.

Hypothenus = sqrt ( 3^2 + 2^2 )

Hypothenus = sqrt ( 9 + 4 )

Hypothenus = sqrt (13)

Hypothenus = √13

1.) Sin(x) = opposite/hypothenus = 3/√13

Rationalise

3/√13 × √13/√13

3√13/13

Sin(2x) = 2 × 3√13/13

Sin(2x) = 6√13/13

2.) Cos( x ) = adjacent/hypothenus

Cos (x) = 2/√13

Rationalise

2/√13 × √13 /√13

2√13/13

Cos(2x) = 2 × 2√13/13

Cos(2x) = 4√13/13

3.) Tan (x) = 3/2

tan (2x) = 2 × 3/2

Tan(2x) = 3

4 0

3 years ago