Which polynomial represents the algebra tile configuration shown?

Mathematics

2 answers:

mariarad [96]2 years ago

7 0

Answer: I’m pretty sure the answer is D. −x^2 + 3x − 4

Step-by-step explanation:

kiruha [24]2 years ago

5 0

Answer:-x^2 + 3x - 4

Step-by-step explanation:

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What is the area of the figure?

Mrrafil [7]

Answer:

The shape has a total area of 14.96cm²

Step-by-step explanation:

To solve this all you need to do is take the area of the outer rectangle, and subtract the area of the inner rectangle.

The outer rectangle is 5.6 by 6.4 cm. To get its area, just multiply those dimensions. When you do so you get the area 35.84cm².

Next the inner rectangle needs to be subtracted. First though, we need its width, which we're not directly given.

We do however know the width of the entire shape, and the width of segments left after cutting out the inner rectangle. All we need to do then is subtract the later from the former to the the inner rectangle's width:

5.6cm - 1.2cm - 0.8cm = 3.6cm

Great! The inner rectangle has an area of 3.6cm × 5.8cm. That gives us 20.88cm².

The final step is to subtract that 20.88 square cm from the 35.84 that we already have. Doing so gives us a result of 14.96cm², and that is the final answer.

5 0

2 years ago

Read 2 more answers

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,

tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let $\bar X$ = sample mean diameter

The z score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ ~ N(0,1)

where, $\mu$ = population mean diameter = 141 millimetres

$\sigma$ = standard deviation = 7 millimetres

n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P( $\bar X$ > 141.4 millimetres)

P( $\bar X$ > 141.4) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ > $\frac{141.4-141}{\frac{7}{\sqrt{39} } } }$ ) = P(Z > 0.36) = 1 - P(Z $\leq$ 0.36)