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Usimov [2.4K]
4 years ago
10

For the reaction VCl2 + Cl2 → VCl5, what are the reactants, products, and correct coefficients in the balanced equation?

Chemistry
2 answers:
egoroff_w [7]4 years ago
5 0

2VCl2 + 3Cl2 -> 2VCl5

Reactants: 2VCl2 and 3Cl2

Product: 2VCl5

To balance the equation, set up a chart with the reactants and products on separate sides. On one side should be V - 1 and Cl - 4 with a line and on the right side should be V - 1 and Cl - 5.

The numbers correspond with the subscripts. To balance, use the biggest compound (VCl5) and multiply that by 2 in order to get an even number for both of 2 and 10. For the reactants, you now need to multiply to get corresponding amounts.

Hope this helps!

enyata [817]4 years ago
5 0

Answer:

Reactants: 2VCl2 and 3Cl2

Product: 2VCl5

Explanation:

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A gas occupies 525 mL at a pressure of 45.0 kPa. What would the volume of the gas be at a pressure of 65.0 kPa
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Boyle's Law is a gas law that relates the pressure and volume of a certain amount of gas, without temperature variation, that is, at constant temperature.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. In other words, the product P · V remains constant at the same temperature:

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Being P1 and V1 the pressure and volume in state 1 and P2 and V2 the pressure and volume in state 2 are fulfilled:

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In this case:

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45,000 Pa* 0.525 L= 65,000 Pa*V2

Solving:

V2=\frac{45,000 Pa* 0.525 L}{65,000 Pa}

V2=0.363 L=363 mL

<u><em>The volume of the gas at a pressure of 65.0 kPa would be 363 mL</em></u>

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