Answer:
165.726 g.
Explanation:
- For the balanced equation:
<em>Cr₂O₃ + 3H₂S → Cr₂S₃ + 3H₂O,</em>
It is clear that 1 mol of Cr₂O₃ and 3 mol of H₂S to produce 1 mol of Cr₂S₃ and 3 mol of H₂O.
- Firstly, we need to calculate the no. of moles of 324.8 g of chromium(III) sulphide:
no. of moles of Cr₂S₃ = mass/molar mass = (324.8 g)/(200.19 g/mol) = 1.62 mol.
- Now, we can find the "no. of grams" of H₂S are needed:
<u><em>Using cross multiplication:</em></u>
3 mol of H₂S produces → 1 mol of Cr₂S₃, from stichiometry.
??? mol of H₂S produces → 1.62 mol of Cr₂S₃.
∴ The no. of moles of H₂S are needed = (3 mol)(1.62 mol)/(1 mol) = 4.86 mol.
∴ The "no. of grams" of H₂S are needed = (no. of moles of H₂S)(molar mass of H₂S) = (4.86 mol)(34.1 g/mol) = 165.726 g.
Answer: 29.0 years
Explanation:
Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.


b) for decomposition of 80 % of reactant



The age of a suspected vintage wine that is 20 % as radioactive as a freshlybottled specimen is 29.0 years
Each mole of a substance contains 6.02 x 10²³ particles
Atoms of Fe = 4.5 x 6.02 x 10²³
= 2.709 x 10²⁹ atoms
To find the density of any sample, you need to know the Mass (grams), and its Volume (measured in mL or cm³). Divide the mass by the volume in order to get a sample's Density.
Density (P)= Mass(m)/Volume(V)
P=m/V
P=245.8grams/94ml
<span>P=2.65grams per ml </span>
Answer: Option (A) is the correct answer.
Explanation:
In real gases, there exists force of attraction between the molecules at low temperature and high pressure. This is because at low temperature there occurs a decrease in kinetic energy of gas molecules and high pressure causes the molecules to come closer to each other.
As a result, forces of attraction increases as molecules come closer to each other and therefore, gases deviate from an ideal gas behavior.
And, at low pressure and high temperature there exists no force of attraction or repulsion between the molecules of a gas because they have high kinetic energy. Hence, gases behave ideally at these conditions.
Thus, we can conclude that the statement as the temperature approaches 0 K, the volume of the ideal gas will be larger than the volume of
because ideal gases lack inter-molecular forces, is true.